Answer:
As the capacitor is discharging, the current is increasing
Explanation:
Lets take
C= Capacitance
L=Inductance
V=Voltage
I= Current
The total energy E given as
We know that total energy E is conserved so when electric energy 1/2 CV² decreases then magnetic energy 1/2 IL² will increases.
It means that when charge on the capacitor decreases then the current will increase.
As the capacitor is discharging, the current is increasing
d=235m
Alpha=35⁰
h=d×sin(alpha)=134.8m
L=d×cos(alpha)=192.5m
Answer:
i) FALSE, ii) TRUE, iii) FALSE, iv) FALSE
Explanation:
When light (electromagnetic radiation) travels through a material medium, its speed is less than the speed of light in a vacuum. If we define the index of parts
n = c / v
where v is the speed of light in the material medium.
The direction of the ray can be determined by the law of refraction
n₁ sin θ₁ = n₂ sin θ₂
Let's apply these equations to our case where
nₓ <n_y
i) The expression of the refractive index
nₓ < n_y
v_y <vₓ
therefore the expression is FALSE
ii) If we use the law of refraction, the light, when passing from a medium with a lower start to another with a higher index, must approach the normal one, away from what would be the continuation of the path of the incident ray
so the expression is TRUE
iii) The speed of light is constant in all material media
the statement is FALSE
iv) light approaches normal
Let me clarify that the normal is a line perpendicular to the surface at the point of contact, not the direction of Io.
the statement of FALSE