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Natalka [10]
2 years ago
8

Need help on this, I never learned how to do this yet and it’s on homework

Mathematics
1 answer:
Wewaii [24]2 years ago
5 0

For a function f(x), its average rate of change on an interval [a, b] is given by what's called the "difference quotient",

\dfrac{f(b)-f(a)}{b-a}

and is basically the ratio of the difference in values of f(x) at the endpoints to the difference in the endpoints themselves.

I assume the 6 intervals below each table correspond to each table immediately above them.

From the first table, we get the following average rates of change (after arranging the intervals from left to right):

• [-3, -2] : (f(-2) - f(-3)) / (-2 - (-3)) = (7 - 12)/1 = -5

• [-2, -1] : (f(-1) - f(-2)) / (-1 - (-2)) = (4 - 7)/1 = -3

• [-1, 0] : (f(0) - f(-1)) / (0 - (-1)) = (3 - 4)/1 = -1

• [0, 1] : (f(1) - f(0)) / (1 - 0) = (4 - 3)/1 = 1

• [1, 2] : (f(2) - f(1)) / (2 - 1) = (7 - 4)/1 = 3

• [2, 3] : (f(3) - f(2)) / (3 - 2) = (12 - 7)/1 = 5

Just do the same for the other two tables. Note that each listed interval has length 1, so practically, each average rate of change over [a, b] is exactly f(b) - f(a).

For parts (c) and (d):

• (c) You'll notice that each of the average rates of change are odd numbers …

• (d) … but they're not necessarily all the same size, and they follow slightly different patterns.

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Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume (V) is calculated by:

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The percentage decrease in the volume of the tumor (\%V) is expressed by:

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The absolute decrease in the volume of the tumor is:

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The percentage decrease is finally simplified:

\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%

Given that R_{o} = R and R_{f} = 0.77\cdot R, the percentage decrease in the volume of tumor is:

\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%

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The volume of the tumor experimented a decrease of 54.34 percent.

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