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xenn [34]
3 years ago
12

The owner of a bike shop sells unicycles and bicycles and keeps inventory by counting seats and wheels. One day, she counts 21 s

eats and 30 wheels. The equation representing the total number of seats is u + b = 21 where u is the number of bicycles and b is the number of bicycles.
A. 2u + b = 21
B. u + 2b = 30
C. 2u + b = 30
D. u + 2b = 21
Mathematics
2 answers:
Sholpan [36]3 years ago
8 0

Answer:

The correct option is:

B. u + 2b = 30

Step-by-step explanation:

The owner of a bike shop sells unicycles and bicycles and keeps inventory by counting seats and wheels. One day, she counts 21 seats and 30 wheels.

u is the number of unicycles and b is the number of bicycles.

There are total 21 seats

⇒  u+b=21

unicycle has 1 wheel and bicycle has 2 and total there are 30 wheels

⇒ u+2b=30

Hence, the correct option is:

B. u + 2b = 30

bearhunter [10]3 years ago
5 0
The wheels function is:

w=2b+u and w=30 so

u+2b=30


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viva [34]

Answer:

- 10

Step-by-step explanation:

Order of operations:  PEMDAS

Multiply first then add

-4 + -6 = -10

8 0
3 years ago
HELP ASAP 6TH GRADE MATH I WILL GIVE BRAINLIEST
Alisiya [41]
It would be letter a
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2 years ago
Which expression is equivalent to 2 (14x-37+28x+12.2-5y-17.5)?
ziro4ka [17]

Answer:

A. 84x - 16y - 10.6

Explanation:

\sf \rightarrow 2(14x-3y+28x+12.2-5y-17.5)

\sf \rightarrow 2 (42x-8y-5.3)

apply distributive method: a(b + c) = ab + ac

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7 0
1 year ago
Situation:
FromTheMoon [43]

Answer:

5.6 days

Step-by-step explanation:

We are given;

Initial Mass; N_o = 25 g

Mass at time(t); N_t = 25/2 = 12.5 (I divide by 2 because we are dealing with half life)

k = 0.1229

Formula is given as;

N_t = N_o•e^(-kt)

Plugging in the relevant values;

12.5 = 25 × e^(-0.1229t)

e^(-0.1229t) = 12.5/25

e^(-0.1229t) = 0.5

(-0.1229t) = In 0.5

-0.1229t = -0.6931

t = -0.6931/-0.1229

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4 0
3 years ago
An industrial expert claims that the average useful lifetime of a typical car transimssion which comes with ten years warranty i
grin007 [14]

Answer:

Step-by-step explanation:

The question is incomplete. The missing information is the group of answer choices. The group of answer choices are

a) none of the above

b) Data provides sufficient evidence, at 1% significance level, to reject the expert's claim. In addition the p-value (or the observed significance level) is equal to P( T < -3.281).

c) Data provides insufficient evidence, at 1% significance level, to support the expert's claim. In addition the p-value (or the observed significance level) is equal to P( Z > 2.896).

d) Data provides sufficient evidence, at 1% significance level, to support the expert's claim. In addition the p-value (or the observed significance level) is equal to P( T >3.355).

e) Data provides insufficient evidence, at 1% significance level, to support the researcher's claim. In addition the p-value (or the observed significance level) is equal to P(Z > 2.896).

Solution:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ ≥ 10

For the alternative hypothesis,

µ < 10

This is a left tailed test.

Since the number of samples is small and the population standard deviation is not given, the distribution is a student's t.

Since n = 9,

Degrees of freedom, df = n - 1 = 9 - 1 = 8

t = (x - µ)/(s/√n)

Where

x = sample mean = 13.5

µ = population mean = 10

s = samples standard deviation = 3.2

t = (13.5 - 10)/(3.2/√9) = 3.28

Since α = 0.01, the critical value is determined from the t distribution table. Recall that this is a left tailed test. Therefore, we would find the critical value corresponding to 1 - α and reject the null hypothesis if the test statistic is less than the negative of the table value.

1 - α = 1 - 0.01 = 0.99

The negative critical value is - 2.896

Since - 3.28 is lesser than - 2.896, then we would reject the null hypothesis.

By using probability value,

We would determine the p value using the t test calculator. It becomes

p = 0.0056

Level of significance = 1%

Since alpha, 0.01 > than the p value, 0.0056, then we would reject the null hypothesis. Therefore, At a 1% level of significance, the sample data showed significant evidence that the average useful lifetime of a typical car transimssion which comes with ten years warranty is significantly less than 10 years

The correct option is

a) none of the above

8 0
3 years ago
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