Answer:
given chord AB=chord CD
L and M are the mid-points of two equal chords AB and CD of a circle
we have
(Equal chords are equidistant from the centre)
In ∆ OLM
OL = OM
<OLM= <OMLbase angles
opposite to equal sides of a A
But <OLA = <OMC(Each = 90°being perpendicular )
On adding
<OLM+<OLA = <OML+<OMC
=<ALM = <CML
Answer:
16.
x<5
hope this helps!!:)
Step-by-step explanation: