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Serhud [2]
4 years ago
7

Using Pythagorean inequalities, determine which of the following sets of values can represent the lengths of the sides of a righ

t triangle.
Mathematics
1 answer:
ivolga24 [154]4 years ago
6 0
The identities are:
If c^2 > a^2 + b^2 the triangle is an obtuse triangle
If c^2 < a^2 + b^2 then triangle is an acute triangle
If c^2 = a^2 + b^2 the triangle is a right triangle
The longest length always goes in for C.
A.  6^2 <,>,= 4^2 + 5^2
36 <,>,= 16 + 25
36 ____41  36< 41 acute

B.  19^2 <,>,= 5^2 + 13^2
361 <,>,= 25 + 169
361 ____194  361 > 194 obtuse

C.  25^2 <,>,= 12^2 + 14^2
625 <,>,= 144 + 196
625 <,>,= 340
625  ___ 340  625 > 340 obtuse

D.  75^2 <,>,= 21^2 + 72^2
5625 <,>,= 441 + 5184
5625 <,>,= 5625
5625 = 5625 right triangle
LETTER D
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KATRIN_1 [288]

Answer:

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Step-by-step explanation:

We know that mean is the sum of all the elements divided by the number of elements there are: m = t/n, where m is the mean, t is the total sum, and n is the number of elements.

Here, we are given the mean number of coins for all 27 + 18 = 45 children is 16, so m = 16 and n = 45. Then:

m = t/n

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This t means that the total number of coins that all the boys and girls have is 720 coins.

Now, we also know the mean number of coins for the boys only, which is 14. Since there are 27 boys, then:

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This t means the total number of coins all the boys have.

Subtracting 378 from 720, we get 342, which is the total number of coins the girls have. We also know there are 18 girls, so:

m = t/n

m = 342 / 18 = 19

Thus, the mean is 19 coins.

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