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4 years ago

What is 438,902 rounded to the nearest ten thousand

Mathematics

2 answers:

Ray Of Light [21]4 years ago

7 0

440,000 is rounded to the nearest ten thousandth

alexgriva [62]4 years ago

4 0

440,000; the number three is in the ten thousands place, and given that 8 is larger, 3 will round up to 4, and all the other numbers to the right will be replaced to zeros

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The bobcat bouncers jumping team can jump 18 times in 9 seconds. At this rate, how many jumps can they make in 45 seconds?

prisoha [69]

Answer:

The bobcat bouncers jumping team can jump 90 times in 45 seconds.

Step-by-step explanation:

6 0

3 years ago

SOMEONE HELP?!! ASAP !! I’ll give brainliest!! Please and ty !!

dsp73

Answer:

$(\pi 4^2 (9))-(\pi 2^2 (9))$

and

$339.292 cm^3$

Step-by-step explanation:

This question is simple once you break it down.

Let's concentrate on the outer cylinder.

First, find the volume of the outer cylinder.

The volume of a cylinder is expressed as: $V = \pi r^2 h$

Gathering information from the diagram..

d = 8 cm

h = 9 cm

You can get the radius from the diameter by just dividing the diameter by 2.

$r = \frac{8}{2}=4$

r = 4

Plug everything into the volume equation.

$V = \pi 4^2 (9)$

Don't solve just yet!

Now, find the volume of the inner cylinder.

Do the exact same thing as you did for the outer cylinder.

d = 4 cm

h = 9 cm

$r = \frac{4}{2}=2$

r = 2

Plug everything into the volume equation..

$V = \pi 2^2 (9)$

The question asks for an expression to represent the volume of the large cylinder after the cylindrical hole is removed. This means you need to subtract the volume of the cylindrical hole from the volume for the large cylinder.

Again, the volume for the large cylinder is $V = \pi 4^2 (9)$ and the volume for the cylindrical hole is $V = \pi 2^2 (9)$

This means..

$(\pi 4^2 (9))-(\pi 2^2 (9))$

That is your answer to the first part of the question.

For the second part, just solve.

$(\pi 4^2 (9))-(\pi 2^2 (9))$

$(\pi*16*9)-(\pi*4*9)$