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sesenic [268]
3 years ago
5

Pl help it’s for a grade

Mathematics
2 answers:
Nonamiya [84]3 years ago
6 0
The answer is B hqriethrwjwrhqrg
True [87]3 years ago
5 0
I think the answer is b
I hope this helps :)
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Contact [7]

Answer:704

Step-by-step explanation: multiply

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E^3x.cos4x.sin2x hii please solv this​ you have to differentiate
finlep [7]

Answer:

y = e^{3x}.cos4x.sin2x

=> y' =- 3e^{3x}.4sin4x.2cos2x=-24.e^{3x}.sin4x.cos2x

dy=y'.dx => dy = -24e^{3x}.sin4x.cos2x.dx

Step-by-step explanation:

6 0
3 years ago
One institute mandates that for every 100 items scanned through the electronic checkout scanner at a retail​ store, no more than
ozzi

Answer:

There is a 20% probability that the store selected does not violate the institute scanner accuracy​ standard

Step-by-step explanation:

70 company stores were investigared.

56 violated the​ institute's scanner accuracy standard.

70-56 = 14 did not violate the institute scanner accuracy​ standard.

If 1 of the 70 company stores is randomly​ selected, what is the probability that that store does not violate the institute scanner accuracy​ standard?

This is 14 divided by 70, so:

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There is a 20% probability that the store selected does not violate the institute scanner accuracy​ standard

4 0
3 years ago
I’m stuck can some one help me
abruzzese [7]

Answer:

3) Midpoint is (-4,0.5)

Option A is correct.

4) Midpoint is (2.5,0)

Option B is correct.

5) The factors are (x+4)(x-7)

Option C is correct.

6) The factors are (x+4)(x+2)

Option A is correct.

Step-by-step explanation:

Question 3

Find midpoint of the following:

(2,-7), (-10,8)

The formula used to find midpoint is: Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )

We have x_1=2, y_1=-7, x_2=-10,y_2=8

Putting values and finding midpoint

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2-10}{2},\frac{-7+8}{2} )\\Midpoint=(\frac{-8}{2},\frac{1}{2} )\\Midpoint=(-4,0.5 )

So, Midpoint is (-4,0.5)

Option A is correct.

Question 4

Find midpoint of the following:

(2,-10), (3,10)

The formula used to find midpoint is: Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )

We have x_1=2, y_1=-10, x_2=3,y_2=10

Putting values and finding midpoint

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2+3}{2},\frac{-10+10}{2} )\\Midpoint=(\frac{5}{2},\frac{0}{2} )\\Midpoint=(2.5,0 )

So, Midpoint is (2.5,0)

Option B is correct.

Question 5

Factor each completely

x^2-3x-28

We will break the middle term and find factors

x^2-3x-28\\=x^2-7x+4x-28\\Taking\:common\\=x(x-7)+4(x-7)\\=(x+4)(x-7)

So, the factors are (x+4)(x-7)

Option C is correct.

Question 6

Factor each completely

x^2+6x+8

We will break the middle term and find factors

x^2+6x+8\\=x^2+4x+2x+8\\=x(x+4)+2(x+4)\\=(x+4)(x+2)

So, the factors are (x+4)(x+2)

Option A is correct.

7 0
3 years ago
Question
Serggg [28]

Answer:

i think two months im not sure tho

Step-by-step explanation:

5 0
3 years ago
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