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geniusboy [140]
2 years ago
14

Please solve! It's not A.

Mathematics
2 answers:
bixtya [17]2 years ago
7 0

Answer:

line 2?

Step-by-step explanation:

yawa3891 [41]2 years ago
3 0
It’s line 2 I took the test I found the answer in quizlet
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Consider the question of whether the home team wins more than half of its games in the National Basketball Association. Suppose
spayn [35]

Answer:

0.0037 = 0.37% probability that the home team would win 65% or more of its games in a simple random sample of 80 games

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

The home team therefore wins 50% of its games

This means that p = 0.5

Determine the probability that the home team would win 65% or more of its games in a simple random sample of 80 games

Sample of 80 means that n = 80 and, by the Central Limit Theorem:

\mu = p = 0.65

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.5*0.5}{80}} = 0.0559

This probability is 1 subtracted by the pvalue of Z when X = 0.65. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.65 - 0.5}{0.0559}

Z = 2.68

Z = 2.68 has a pvalue of 0.9963

1 - 0.9963 = 0.0037

0.0037 = 0.37% probability that the home team would win 65% or more of its games in a simple random sample of 80 games

7 0
2 years ago
(4x^3 - x^2 +4x) + (x^3 -x^2 - 4x)
madreJ [45]

Answer:

5x³ - 2x²

Step-by-step explanation:

Step 1: Write out expression

4x³ - x² + 4x + x³ - x² - 4x

Step 2: Combine like terms (x³)

5x³ - x² + 4x - x² - 4x

Step 3: Combine like terms (x²)

5x³ - 2x² + 4x - 4x

Step 4: Combine like terms (x)

5x³ - 2x²

4 0
3 years ago
56 with 75% increase
valina [46]

Answer:133

Step-by-step explanation:

7 0
3 years ago
Please show how to compute these values. Thank you.
alekssr [168]

Answer: ln ( 40) *100

Step-by-step explanation:

Substituting 140 in the equation,

140 = 100 + e^(.01q)

40 = e^(.01q)

Take the natural log of bot hsides

ln ( 40) = .01q

q= ln ( 40 ) * 100

6 0
2 years ago
Find <br><img src="https://tex.z-dn.net/?f=%28%20%7B4x%7D%5E%7B2%7D%20%20%2B%203x%29%20%2B%20%28%20%7B7x%7D%5E%7B2%7D%20%20-%205
marishachu [46]

Answer:

11x^2-2x-6

Step-by-step explanation:

(4x^2+3x)+(7x^2-5x-6)= \\\\(4x^2+7x^2)+(3x-5x)-6= \\\\11x^2-2x-6

Hope this helps!

4 0
3 years ago
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