Answer:
There is a 13.61% probability that exactly 4 of the jobs were not completed within the bid time.
Step-by-step explanation:
For each job, there are only two possible outcomes. Either they are completed on time, or they are not. This means that we use the binomial probability distribution to solve this problem.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which 
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
Looking at a random sample of 8 jobs that it has contracted, calculate the probability that exactly 4 of the jobs were not completed within the bid time.
There are 8 jobs, so 
.
30% of them are finished on time, which means that 70% are not completed within the bid time. This means that 
The problems asks for P(X = 4). So
There is a 13.61% probability that exactly 4 of the jobs were not completed within the bid time.
Question 1
2x + 4 + x - 7 = 3(x-7)
Add like terms, x-terms add
3x + 4 - 7 = 3(x-7)
Subtract 7 from 4
3x - 3 = 3(x-7)
Multiply out right side with distributive property, 3 times x, and 3 times -7
3x -3 = 3x - 21
Add 21 on each side to cancel -21 on right
3x + 18 = 3x
This is impossible, 3x + 18 cannot equal 3x, plug value in to check, 3(1) + 18 = 3(1), 21 not equal to 3
Question 1 Answer : No Answer
Question 2
4(m-2) = -3(m-16)
Multiply using distributive property on each side
4m - 8 = -3m + 48
Add 8 on each side to cancel -8 on left
4m = -3m + 56
Add 3m on each side to cancel -3m on right
7m = 56
Divide 7 on each side to make 7m : m
m = 56/7
m = 8
Answer to Question 2 : 8
Answer:
ᴡʜᴀᴛ ............................
Use the Quotient Rule; x^a/x^b = x^a - b
y = 2 × 3^2 - 1
Simplify 2 - 1 to 1
y = 2 × 3^1
Use the Rule of One: x^a = x
y = 2 × 3
Simplify 2 × 3 to 6
<u>y = 6</u>
