The diagonal fencing will be the hypotenuse of a right triangle with sides 120yds long so:
h=√2(120^2))
h=√28800 yd
And the surrounding fencing will just be four times the side length of 120yds so:
s=480yd
So the total fencing needed is:
f=480+√28800 yards
f≈649.71 yd (to nearest hundredth of a yard) which is
f≈650 yds (to nearest whole yard)
But, I wasn't sure, if they just want the diagonal fencing needed then it is just:
f=√28800
f≈170 yds (to nearest yard)
29/48 is about 60 percent to the nearest hundredth
The bottom two because they rapidly go up or down super fast. If it’s an exponential function, it will start off as super low or super high and then shoot up or down rapidly
Simple, the area is 80*50, 80*50=4,000 ft², the backyard has a dimension of 50*40=2,000 ft², subtract 4,000 from 2,000, 4,000-2,000=2,000 ft²
Answer:
<em>(1). A = 18 cm² ; (2). TR = 18 units</em>
Step-by-step explanation:
