Answer:
20% alcohol = 1 gal
10% alcohol = 9 gal
Step-by-step explanation:
Let
x = 20% alcohol
y = 10% alcohol
x + y = 10 (1)
0.20x + 0.10y = 10*0.11
0.20x + 0.10y = 1.1 (2)
From (1)
x = 10 - y
Substitute x = 10 - y into (2)
0.20x + 0.10y = 1.1
0.20(10 - y) + 0.10y = 1.1
2 - 0.20y + 0.10y = 1.1
- 0.20y + 0.10y = 1.1 - 2
-0.10y = -0.9
y = -0.9/-0.10
y = 9 gal
substitute y = 9 into (1)
x + y = 10
x + 9 = 10
x = 10 - 9
x = 1 gal
20% alcohol = 1 gal
10% alcohol = 9 gal
8*4-4/2+1
32-4/2+1
32-2+1
=31 answer
So, the answer to this question is 31
Domain- {-2, 1, 0, 1, 2}
Range- {-2, 0, 2}
My domain is right but I don’t think my range is. I did learn this 4 years ago though so
Answer:
-3yc+3y2+8c-8y
Step-by-step explanation:
(3y-8)(-c+y)
3y(-c+y)-8(-c+y)
-3yc+3y2+8c-8y
