3x^2+20x+12 pls show work ;-;

Mathematics

1 answer:

RoseWind [281]2 years ago

5 0

Answer:

$3 {x}^{2} + 20x + 12 \\ 3 {x}^{2} + 18x + 2x + 12 \\ 3x(x + 6) + 2(x + 6) \\( 3x + 2)(x + 6)$

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Which expression is equivilent to 6(3x-4)+2x

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44x,

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Jenny opened a package of screws quickly and many of them spilled on the floor. She needs to organize the fasteners according to

hichkok12 [17]

We have to compare diameters and arrange them in order smallest to greatest

We can see units for option A and B are in square inches so they represents area. So first we will find diameter from area using formula

$A = \pi r^{2}$

so for choice (A) area is given as $4.375 \times 10^{7}$ . So plug this in A place in formula and then solve for radius r

$4.375 \times 10^{7} = \pi r^{2}$

$\frac{4.375 \times 10^{7}}{\pi} = \frac{\pi r^{2}}{\pi}$

$1.393 \times 10^{7} } = r^{2}$

$\sqrt{1.393 \times 10^{7}} = \sqrt{r^{2}}$

3731.76 = r

So screw A will have
$diameter = 2 \times r = 2 \times 3731.76 = 7463.52$ inches

Similarly for choice (E) area is $1.428 \times 10^{1} = 14.28$
so again plug in formula

$A = \pi r^{2}$

$14.28 = \pi r^{2}$

$\frac{14.28}{\pi} = \frac{\pi r^{2}}{\pi}$

$4.5477 = r^{2}$

$\sqrt{4.5477} = \sqrt{r^{2}}$

2.13201 = r

So screw E will have
$diameter = 2 \times r = 2 \times 2.13201 = 4.26402$ inches

So diameters of all screws are as follows:

Screw A: 7463.52 inches
Screw B: 1.5 inches
Screw C: $1\frac{7}{8} = \frac{1\times 8+7}{8} = \frac{15}{8} = 1.875$ inches
Screw D: 0.25 inches
Screw E: 4.26402 inches

Comparing all numbers 7463.52, 1.5, 1.875, 0.25, 4.26402 we can see that smallest number is 0.25, then comes 1.5, then 1.875 and then 4.26402 and then 7463.52

So order from least to greatest will be screw D (0.25), B(1.5), C(1.875), E (4.26402), A (7463.52).

So thats the order D,B,C,E,A and the final answer