The slope of the line is the change in y values over the change in x values, since for horizontal line, the y values do not change then, the slope is zero.
If the line is horizontal, this means that whatever the value of the x-coordinate (abscissa) is, the y-coordinate (ordinate) will always be 10.
The intercept of the line is 10. So, third statement is not true.
Since the equation of the line is zero and its y-intercept is zero, using the equation of the line which is,
y = mx + b
where m is slope and b is y-intercept. The equation of the line is,
y = 0x + 10 ; y = 10
<em>The true statements for this item are 1st, 2nd, and 4th.</em>
Answer:
First of all which question are you asking me to do?
Second of all you can also just ask a parent/guardian to help you.
Answer:
5/8
Decimal Form: 0.625
Step-by-step explanation:
Cancel 6.
−5×-5/8*1/5
cancel 5
- -5/8
Move the negative sign to the left.
- (-5/8)
remove parentheses
answer is 5/8
hope i helped
-lvr
Answer:
Step-by-step explanation:
okay i will answer but i dont see the question
Given:
g(x) = (1/3)x + 2
Part (a)
To find the inverse:
Set y = g(x) = (1/3)x + 2
Swap x and y.
x = (1/3)y + 2.
Solve for y.
(1/3)y = x - 2
y = 3(x - 2).
Set g⁻¹(x) to y.
Answer: g⁻¹(x) = 3(x - 2)
Part (b)
Create the table shown below to graph g(x) and g⁻¹(x).
x g(x) g⁻¹(x)
---- --------- ---------
-8 - 2/3 - 30
-6 0 - 24
-4 2/3 - 18
-2 4/3 - 12
0 2 - 6
2 8/3 0
4 4/3 6
6 4 12
8 14/3 18
Note that when x = -6, g(x) = 0, so that (-6, 0) lies on he black liine.
Therefore the inverse function should yield (0, -6) to be correct. This is so, so g⁻¹ is correct.
Both g(x) and g⁻¹(x)satisfy the vertical line test, so both are functions.
Part (c)
Algebraically, we know that g⁻¹(x) is correct if g(g⁻¹(x)) = x
Use function composition to obtain
g(g⁻¹(x)) = (1/3)*(3x - 6) + 2
= x - 2 + 2
= x
Therefore g⁻¹(x) is correct.