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3 years ago

Help me please. I dont really understand this.

Computers and Technology

2 answers:

nadezda [96]3 years ago

7 0

A ratio is a group of 2 numbers: part to part or whole to part.

Sorry if my explaining is bad.

Hope this helps!

vaieri [72.5K]3 years ago

7 0

Ratio is how many there is of a kind

Like in the photo there are 4 cars and 3 dogs

You might be interested in

Which game would be classified as an educational game

Masja [62]

Answer:

The various game types can be like board, video and card games. As far as educational video games are concerned they are made to explain to us some of the subjects which can be specific, as well as to teach a certain set of skills like role-playing. They are the interactive play that can help us learn the rules, goals, techniques to solve the problems. adaptation quality, as well as interactions, and all of these are being narrated in the form of a story. You should know that each game is a story in reality, and always. One can think of many such games, and like action games based on the military helps us learn how to fight a war.

Explanation:

Please check the answer.

7 0

3 years ago

All cells in row 2 through 5 are referred as 2:5 true or false

Simora [160]

<h3>Answer:</h3><h2>TRUE</h2>

Explanation:

BRAINLIEST PLSSSSSSSSSSSSSSSSSSS

8 0

3 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

3 years ago

Which of the following resources is an example of a web-based application?

kompoz [17]

The answer will be google docs since it depends on a web and its an application. hope it helps

3 0

3 years ago

PLEASE HURRY

creativ13 [48]

I'm pretty sure it's C) or D) because it seems those make the most sense because providing excitement does not matter if that is not their point, repeating a previous point is practically useless because that point has already been said.

5 0

3 years ago

Read 2 more answers