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Kazeer [188]
2 years ago
14

Which types of file formats are the best choice for files that may need to be edited later?

Computers and Technology
1 answer:
Yanka [14]2 years ago
5 0

Answer:

PSD, PNG, TIFF

Explanation:

JPEGs compress image data, which leads to random pixels, it is especially disastrous for digital artists in the field of Pixel Art, as it causes blurry pixels.

PSDs are files saved by Photoshop, an image editing program

PNGs are your average run of the mill images that are commonly used in many art tools like Piskel or Aseprite

TIFFs are used for high-quality raster-type graphics, they are generally used in software programming, specifically for graphics. It supports lossless compression or in layman's terms, no image data is lost during the compression process.

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/* ELEN 1301 Programming Assignment #5. Name : Your name. Student ID : Your student ID #. Due date : Due date Purpose of the pro
cestrela7 [59]

Answer:

Here is the C++ program:

#include<iostream> //to use input output functions

#include<iomanip> //to use setprecision

using namespace std; //to identify objects cin cout

int main() { //start of main function

     int n1, n2, n3, n4, n5, n6, n7, min, max;  // declare variables for 7 numbers, minimum value and maximum value

     double sum= 0; //declare variable to hold sum of 7 numbers

     double average;  //declare variable to hold average of 7 numbers

     cout<<"Enter first number: "; //prompts user to enter 1st number

     cin>>n1; //reads first number from user

     max = n1; //sets the first number to maximum

     min=n1; //sets the first number to minimum

     cout<<"Enter second number: "; //prompts user to enter 2nd number

     cin>>n2; //reads second number from user

     if(n2<min){ //if second number is less than min

          min=n2;      } //sets min to n2

     if(n2>max){ //if n2 is greater than max

          max = n2;      } //sets max to n2

     cout<<"Enter third number: ";  //prompts user to enter 3rd number

     cin>>n3; //reads third number from user

     if(n3<min){ //checks if n3 is greater than min

          min=n3;      } //sets n3 to min

     if(n3>max){ //checks if n3 is greater than max

          max = n3;      }      //sets max to n3

    cout<<"Enter fourth number: ";//prompts user to enter 4th number

     cin>>n4; //reads fourth number from user

     if(n4<min){  //if n4 is less than min

          min=n4;      }  //sets min to n4

     if(n4>max){  //if n4 is greater than max

          max = n4;      }  //sets max to n4

     cout<<"Enter fifth number: "; //prompts user to enter 5th number

     cin>>n5; //reads fifth number from user

     if(n5<min){  //if n5 is less than min

          min=n5;     }  //sets min to n5

     if(n5>max){  //if n5 is greater than max

          max = n5;      }  //sets max to n5

     cout<<"Enter sixth number: "; //prompts user to enter 6th number

     cin>>n6; //reads sixth number from user

     if(n6<min){ // if n6 is less than min

          min=n6;      }  //sets min to n6

     if(n6>max){  //if n6 is greater than max

          max = n6;      }  //sets max to n6

     cout<<"Enter seventh number: ";//prompts user to enter 7th number

     cin>>n7; //reads seventh number from user

     if(n7<min){  //if n7 is less than minimum number

          min=n7;      }  //assigns n7 to min

     if(n7>max){  //if n7 is greater than the maximum number

          max = n7;      }  //assigns n7 to max

     sum = n1+n2+n3+n4+n5+n6+n7;  //adds 7 numbers

     average = sum/7;  //computes average of 7 numbers

     cout<<"The average is: "<<fixed<<setprecision(3)<<average<<endl; //displays average value up to show 3 digits below decimal point using setprecision method of iomanip library

     cout<<"The maximum number is: "<<max<<endl; //displays maximum number of 7 numbers

     cout<<"The minimum number is: "<<min<<endl;  //displays miimum number of 7 numbers    

     return 0; }

Explanation:

The program is well explained in the comments attached to each statement of program. For example if

n1 = 3

n2 = 9

n3 = 7

n4 = 6

n5 = 2

n6 = 5

n7 = 4

When n1 is read using cin then this number is set to max and min as:

min = 9

max = 3

Now when n2 is read, the first if condition checks if n2 is less than min and second if condition checks if n2 is greater than max. As n2 = 9 so it is not less than min so this if condition is false and n2 is greater than max i.e. 3 so this condition is true. So 9 is assigned to max.

min = 9

max = 9

Now when n3 is read the values of min and max become:

min = 7

max = 9

Now when n4 is read the values of min and max become:

min = 6

max = 9

Now when n5 is read the values of min and max become:

min = 2

max = 9

Now when n6 is read the values of min and max become:

min = 2

max = 9

Now when n7 is read the values of min and max become:

min = 2

max = 9

Now the statement       sum = n1+n2+n3+n4+n5+n6+n7;

executes which becomes:

sum = 3 + 9 + 7 + 6 + 2 + 5 + 4

sum = 36.0

Next program control moves to statement:

average = sum/7;

this becomes

average = 36/7

5.142857

Since this is to be displayed up to 3 decimal places so average = 5.143

the complete output of the program is attached.

3 0
3 years ago
Davis wants to attach a scanner to his computer. How will he do this?
Aleksandr [31]
It would often connect via a universal serial bus (USB) cable, so answer [B].
8 0
3 years ago
Read 2 more answers
A lot of practice is required to develop the speed and skill needed to prevent ____.
Angelina_Jolie [31]
Being a quitter, because you can’t have that quit mentality
7 0
2 years ago
What makes a GOOD algorithm choose?
julia-pushkina [17]

Answer: I'd go with Efficiency and Correct.

7 0
2 years ago
You want to know your grade in Computer Science, so write a program that continuously takes grades between 0 and 100 to standard
Dominik [7]

Answer:

Following are the program in the Python Programming Language.

#declare variables and initialize to 0

s=0

n=0

avg=0

#set the infinite while loop  

while(True):

 #get input from the user

 score=input()

 #set if statement to break loop

 if(score =="stop"):

   break

 #otherwise, perform calculation

 else:  

   n+= 1

   s=s+ int(score)

   avg= s/n

#print average of the input

print ('average: ',avg)

<u>Output</u>:

58

96

34

15

stop

average:  50.75

Explanation:

<u>Following are the description of the program</u>.

  • Firstly, set three variable that is 's' for sum, 'n' for count and 'avg' for average and initialize them to 0.
  • Set the infinite while loop and inside it, set variable 'score' that get input from the user then, set the if conditional statement for break the loop, otherwise we calculate the sum of the user input and calculate its average.
  • Finally, we print the result with message.
6 0
3 years ago
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