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xxTIMURxx [149]
4 years ago
11

Which of the following sets of numbers could be the lengths of the sides of a triangle? A. 3 ft, 6 ft, 9 ft B. 3 ft, 5 ft, 7 ft

C. 3 ft, 6 ft, 12 ft D. 3 ft, 9 ft, 27 ft
Mathematics
1 answer:
Whitepunk [10]4 years ago
4 0
Answer:
<span>B. 3 ft, 5 ft and 7 ft
</span>
Explanation:
In any triangle, the sum of any two sides must be greater that the third one.

Therefore, to know if the given sides represent a triangle or not, all what we will do is add the two short sides and compare the result to the largest one.
We would have 3 options:
sum of short sides > longest side ......> It is a triangle
sum of short sides < longest side ......> It is not a triangle
sum of short sides = longest sides ....> It is not a triangle

Now, for the given:
1- Option A:
sum of short sides = 3 + 6 = 9 ft which is equal to the longest side
This option is incorrect

2- Option B:
sum of short sides = 3 + 5 = 8 ft which is greater than the longest side
This option is correct

3- Option C:
sum of short sides = 3 + 6 = 9 ft which is less than the longest side
This option is incorrect

4- Option D:
sum of short sides = 3 + 9 = 12 ft which is less than the longest side
This option is incorrect

Based on the above, the only correct option is B.

Hope this helps :)
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Write:<br> 3^-4 in standard form
pav-90 [236]

Answer:

\frac{1}{81}

Step-by-step explanation:

<u>Key skills: Exponents + Fractions</u>

Use the negative exponent property. If your number is x^-y then it would be the same as 1/x^y

3^-4 is the same as \frac{1}{3^{4}}

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4 0
3 years ago
I need help pls!
vredina [299]

Answer:

Step-by-step explanation:

7 feet   1 foot is 12 inches

7*12= 84 inches.

None of the choices are correct.

90 inches is 7.5 feet

62.5 inches is 5.2 feet

75 inches is 6.25 feet

4 0
3 years ago
Hhelp pls lol i don't understand​
sladkih [1.3K]

Answer:

m∠1= 80

m∠2= 100

m∠3= 80

Step-by-step explanation:

Given: m∠1= 2x +40

m∠2= 2y +40

m∠3= x +2y

m∠1 +m∠2= 180 (adj. ∠s on a str. line)

2x +40 +2y +40= 180

2x +2y+ 80= 180

2x +2y= 180 -80

2x +2y= 100

2(x +y)= 100

x +y= 100 ÷2

x +y= 50 -----(1)

m∠1= m∠3 (vert. opp. ∠s)

2x +40= x +2y

2x -x +40= 2y

x= 2y -40 -----(2)

Substitute equation (2) into (1):

2y -40 +y= 50

3y= 50 +40

3y= 90

y= 90 ÷3

y= 30

Substitute y= 30 into equation (2):

x= 2(30) -40

x= 60 -40

x= 20

m∠1

= 2x +40

= 2(20) +40

= 40 +40

= 80

m∠2

= 2y +40

= 2(30) +40

= 60 +40

= 100

m∠3

= x +2y

= 20 +2(30)

= 20 +60

= 80

Alternatively, since m∠1= m∠3,

m∠3

= m∠1 (vert. opp. ∠s)

= 80

5 0
3 years ago
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