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3 years ago

684,658 to nearest one thousand

Mathematics

1 answer:

Vlada [557]3 years ago

3 0

5,000 I guess... sorry if it's wrong. Im just real sleepy right now! Hope it helped (;

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Ordering the Angle Measures of a Triangle

mel-nik [20]

Answer:

C, B, A

Step-by-step explanation:

The sides in order from shortest to longest are ...

AB = m-2

AC = m

BC = m+4

The angles opposite these sides will be in order, smallest to largest. The angle opposite is the one whose letter is not in the line segment name.

C, B, A

7 0

2 years ago

What’s the value of x?

tigry1 [53]

Answer:

x=7

Step-by-step explanation:

7 0

2 years ago

Dentify the location of the values square root of 10, square root of 13, and twenty two ninths on the number line.

Goshia [24]

A number line is a system that shows the location of all directed numbers on a straight line. All numbers can be plotted on a number line. Thus the required answer to the given question is; Option A. Point A is twenty-two ninths, point B is square root of 10, and point C is square root of 13.

A line on which the locations of all directed numbers can be shown is termed a number line. It has two extreme ends ranging from -∞ to +∞. Note that all numbers can be plotted on a number line. So that the position of any given number can be shown on the line.

In the given question, we have:

i. square root of 10 = $\sqrt{10}$

= 3.2

ii. square root of 13 = $\sqrt{13}$

= 3.6

iii. twenty-two ninths = $\frac{22}{9}$

= 2.4

But it has been given that;

Number line with points plotted at; two and four-tenths labeled point A, three and two-tenths labeled point B, and three and six-tenths labeled Point C.

Therefore,

Point A is twenty-two ninths, point B is square root of 10, and point C is square root of 13.

Thus the correct option is A.

For more clarifications on number line visit: brainly.com/question/22567573

#SPJ1

6 0

1 year ago

Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-

ivanzaharov [21]

Answer:

$c = \displaystyle\frac{9}{4}$

Step-by-step explanation:

The following information is missing in the given question:

$f(x) = \sqrt{x}$

Using this we may solve the question as:

We are given the following in the question:

$f(x) = \sqrt{x}, x \in [0,9]$

We have to find the number c such that f(x) satisfies the Mean value theorem.

Mean Value theorem:

It states that if the function is differentiable in the closed interval [a,b], differentiable in the interval (a,b), then there exist c in (a,b) such that:

$f'(c) = \displaystyle\frac{f(b)-f(a)}{b-a}$

Now,

$f(x) = \sqrt{x}\\f'(x) = \frac{1}{2\sqrt{x}}$

Continuity in [0,9]

Since a polynomial function is continuous everywhere, f(x) is continuous in [0,9]

Differentiability in (0,9)

Since a polynomial function is differentiable everywhere the given function is differentiable in interval (0,9)

Then, by mean value theorem:

$f'(c) = \displaystyle\frac{f(b)-f(a)}{b-a}\\\\\frac{1}{2\sqrt{c}} = \frac{f(9) - f(0)}{9-0} = \frac{3}{9}\\\\\frac{1}{2\sqrt{c}} = \frac{1}{3}\\\\c= \frac{9}{4}$

7 0

2 years ago

Someone pls help:) Find the equivalent expressions for (x+7) (x+1)

Margarita [4]

Rvsrsvuofehwecrbfwuibeviubvuivfshdciahbu

7 0

2 years ago

Read 2 more answers