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LenaWriter [7]
3 years ago
9

2

Mathematics
1 answer:
Contact [7]3 years ago
6 0
Answer is C
Each additional year of
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triangle ABC has vertices at A (-12,-8) B (10,-6) and C (6,14. What is the midpoint of side AC of the triangle?
grigory [225]

Step-by-step explanation:

midpoint of AC=(x¹+x²/2,y¹+y²/2)

=(-12+6/2,-8+14/2)

=(-6/2, 6/2)

=(-3,3)

5 0
3 years ago
An iceberg weighs 450,000 pounds if it loss 0.2% of its weight in a day, what is its new weight at the end of the day
marysya [2.9K]

Answer:

449 100

Step-by-step explanation:

0.2% × 450000÷ 100=900

450000-900= 449 100

5 0
3 years ago
Read 2 more answers
How do you solve the inequality 6y+3> -18x
Alex17521 [72]
6y + 3 \ \textgreater \  - 18 x

Subtract 3 from both sides:

6 y + 3 - 3 \ \textgreater \  - 18 x - 3

6y \ \textgreater \  - 18 x - 3

Dividade both sides by 6 :

\frac{6y}{6} \ \textgreater \   \frac{-18x-3}{6}

y \ \textgreater \  \frac{-18x-3}{6}

hope this helps!


6 0
3 years ago
I think I know this much so far for A (but I could be wrong):
Eduardwww [97]
Part A. You have the correct first and second derivative.

---------------------------------------------------------------------

Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.

-------------------------------------------------------------

Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out

To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h  ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0. 
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well. 
6 0
3 years ago
Charles wants to determine which car is the fastest. The actual speed of four cars is shown below: Car A B C D Speed (in km/h) 6
marysya [2.9K]

it would be car d because of what the time was on the chart (i did the test and it was correct)

5 0
3 years ago
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