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NemiM [27]
2 years ago
12

Determine the factors of x^2 - 8x + 16.

Mathematics
2 answers:
Ipatiy [6.2K]2 years ago
6 0

Answer:

B) (x-4)(x-4)

Step-by-step explanation:

x^2-8x+16

(x-4)(x-4)

eimsori [14]2 years ago
5 0
The answer is B. (x-4)(x-4)
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Solve this equation x-3=4
MAXImum [283]

Answer:

x-3= 4

x= 4+3

Answer: x= 7

5 0
3 years ago
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Could someone please help me with this question? 15 points.
polet [3.4K]
1a) f(x) = I x+2 I. This is a piece-wise graph ( V form)
      x = 0 →f(x) =2 (intercept y-axis)
      x = -2→f(x) = 0 (intercept x-axis)
      x = -3→f(x) = 1 (don't forget this is in absolute numbers)
      x = -4→f(x) = 2 (don't forget this is in absolute numbers)
Now you can graph the V graph

1b) Translation: x to shift (-3) units and y remains the same, then
      f(x-3) = I x - 3 + 2 I = I x-1 I
     the V graph will shift one unit to the right, keeping the same y. Proof:
     f(x) = I x-1 I . Intercept x-axis when I x-1 I = 0, so x= 1
8 0
3 years ago
Solve dis attachment and show all work ( I got it all wrong and I want to know how to solve it )
DedPeter [7]
(a) First find the intersections of y=e^{2x-x^2} and y=2:

2=e^{2x-x^2}\implies \ln2=2x-x^2\implies x=1\pm\sqrt{1-\ln2}

So the area of R is given by

\displaystyle\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\left(e^{2x-x^2}-2\right)\,\mathrm dx

If you're not familiar with the error function \mathrm{erf}(x), then you will not be able to find an exact answer. Fortunately, I see this is a question on a calculator based exam, so you can use whatever built-in function you have on your calculator to evaluate the integral. You should get something around 0.5141.

(b) Find the intersections of the line y=1 with y=e^{2x-x^2}.

1=e^{2x-x^2}\implies 0=2x-x^2\implies x=0,x=2

So the area of S is given by

\displaystyle\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}(2-1)\,\mathrm dx+\int_{1+\sqrt{1-\ln2}}^2\left(e^{2x-x^2}-1\right)\,\mathrm dx
\displaystyle=2\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\mathrm dx

which is approximately 1.546.

(c) The easiest method for finding the volume of the solid of revolution is via the disk method. Each cross-section of the solid is a circle with radius perpendicular to the x-axis, determined by the vertical distance from the curve y=e^{2x-x^2} and the line y=1, or e^{2x-x^2}-1. The area of any such circle is \pi times the square of its radius. Since the curve intersects the axis of revolution at x=0 and x=2, the volume would be given by

\displaystyle\pi\int_0^2\left(e^{2x-x^2}-1\right)^2\,\mathrm dx
5 0
3 years ago
Simplify the following and leave your answer in smallest form
LuckyWell [14K]

Answer:

1/59

Step-by-step explanation:

5 0
2 years ago
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WILL GIVE BRAINLIEST
Evgesh-ka [11]
All you have to do is plug in the given values into the given equation and evaluate.

The expression is,

A(t) =  l{e}^{rt}
But we have to analyze the problem carefully. This is a natural phenomenon that can be modelled by a decay function. The reason is that, after every hour we expect the medicine in the blood to keep reducing.

Therefore we use the decay function rather. This is given by,


A(t) =  l{e}^{-rt}

where,

l = 100 \: milligrams

r =  \frac{14}{100}  = 0.14

and

t = 10 \: hours

On substitution, we obtain;

A(10) =  100 \times {e}^{ - 0.14 \times 10}


A(10) =  100 \times {e}^{ - 1.4}



Now, we take our calculators and look for the constant
e

,then type e raised to exponent of -1.4. If you are using a scientific or programmable calculator you will find this constant as a secondary function. Remember it is the base of the Natural logarithm.



If everything goes well, you should obtain;

A(10) =  100 \times 0.24659639


This implies that,


A(10) =  24.66

Therefore after 10 hours 24.66 mg of the medicine will still remain in the system.
3 0
3 years ago
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