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Fantom [35]
2 years ago
5

Which of the following is a solution of the inequality 2x+6y< 10? *

Mathematics
1 answer:
Vsevolod [243]2 years ago
6 0

Answer: Which of the following ordered pairs is a solution of the inequality 2x + 6y ≤ 10?a. (3, 1) b. (2, 2) c. (1, 2) d. (1, 0)Answer:The correct answer among the choices is letter d. From the following choices of ordered pair, (1, 0) is the set solution of the inequality 2x + 6y ≤ 10. Substituting the given pair order make the inequality a true statement.  To counter check answer, substituting the pair order and solving the linear inequality will result a value to support the correct answer.Step-by-step explanation:a. ( 3,1 ) (x ,y)Substitution2x + 6y ≤ 102(3) + 6(1) ≤ 106 + 6 ≤ 1012  ≤ 10 ( The inequality is False)This is not the correct answer since value to solve for x and y should result to an equal or lesser value than 10.b. (2, 2) (x ,y)Substitution2x + 6y ≤ 102(2) + 6(2) ≤ 104 + 12 ≤ 1016  ≤ 10 ( The inequality is False)This is not the correct answer since value to solve for x and y should result to an equal or lesser value than 10.c. (1, 2) (x ,y)Substitution2x + 6y ≤ 102(1) + 6(2) ≤ 102 + 12 ≤ 1014  ≤ 10 ( The inequality is False)This is not the correct answer since value to solve for x and y should result to an equal or lesser value than 10.d. (1, 0) (x ,y)Substitution2x + 6y ≤ 102(1) + 6(0) ≤ 102 + 0 ≤ 102 ≤ 10 ( The inequality is True)The statement states that 2 is lesser than or equal to 10.

Step-by-step explanation:

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Find the quotient of 1 1/4 and 3 1/2 express your answer in simplest form
natta225 [31]

Answer:

11/14

Step-by-step explanation:

11/4 / 3 1/2

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3 years ago
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consider the gre scores for a random sample of 6 students out of a class of 25: name julia andrew jason cathy jessica robert sco
Thepotemich [5.8K]
Name  Score
Julia      650
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Mamont248 [21]

Answer:

(x-4)^2+(y+7)^2=43

Step-by-step explanation:

The standard equation of a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.

We are given that the center is (4, -7) and that the radius is √(43).

So, <em>h</em> = 4, <em>k</em> = -7, and <em>r</em> = √(43). Substitute:

(x-(4))^2+(y-(-7))^2=(\sqrt{43})^2

Simplify. Hence, our equation is:

(x-4)^2+(y+7)^2=43

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