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Fantom [35]
2 years ago
5

Which of the following is a solution of the inequality 2x+6y< 10? *

Mathematics
1 answer:
Vsevolod [243]2 years ago
6 0

Answer: Which of the following ordered pairs is a solution of the inequality 2x + 6y ≤ 10?a. (3, 1) b. (2, 2) c. (1, 2) d. (1, 0)Answer:The correct answer among the choices is letter d. From the following choices of ordered pair, (1, 0) is the set solution of the inequality 2x + 6y ≤ 10. Substituting the given pair order make the inequality a true statement.  To counter check answer, substituting the pair order and solving the linear inequality will result a value to support the correct answer.Step-by-step explanation:a. ( 3,1 ) (x ,y)Substitution2x + 6y ≤ 102(3) + 6(1) ≤ 106 + 6 ≤ 1012  ≤ 10 ( The inequality is False)This is not the correct answer since value to solve for x and y should result to an equal or lesser value than 10.b. (2, 2) (x ,y)Substitution2x + 6y ≤ 102(2) + 6(2) ≤ 104 + 12 ≤ 1016  ≤ 10 ( The inequality is False)This is not the correct answer since value to solve for x and y should result to an equal or lesser value than 10.c. (1, 2) (x ,y)Substitution2x + 6y ≤ 102(1) + 6(2) ≤ 102 + 12 ≤ 1014  ≤ 10 ( The inequality is False)This is not the correct answer since value to solve for x and y should result to an equal or lesser value than 10.d. (1, 0) (x ,y)Substitution2x + 6y ≤ 102(1) + 6(0) ≤ 102 + 0 ≤ 102 ≤ 10 ( The inequality is True)The statement states that 2 is lesser than or equal to 10.

Step-by-step explanation:

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9. The endpoints of a diameter of a circle are A (2,1) and B(5,5). Find the area of the circle in terms of . (1 point)
Georgia [21]

Answer:

Area of the circle is 6.25π sq.unit

Step-by-step explanation:

The centre of the circle is at the mid point of a diameter. Th mid point of the diameter is at (5+22,5+12)or(72,3),which is centre. Radius is the distance from end point (5,5)to centre (72,3)∴r=√(5−72)2+(5−3)2=√1.52+4=√6.25=2.5∴

Area of the circle is Ac=π⋅r2=π⋅2.52=6.25π sq.unit[Ans]

5 0
2 years ago
Read 2 more answers
How do you write 7.25 in word form?
babymother [125]
Seven and twenty five hundredths, or seven and a quarter
4 0
3 years ago
(03.05 MC) Solve the rational equation x divided by 2 equals x squared divided by quantity x minus 2 end quantity, and check for
ycow [4]

Answer:

x = 0 and x = -2 are solutions of the given rational equation.

Step-by-step explanation:

We must solve the following rational equation:

\frac{x}{2} = \frac{x^{2}}{x-2}

Now we present the procedure:

1) \frac{x}{2} = \frac{x^{2}}{x-2} Given

2) x\cdot (x-2) = 2\cdot x^{2} Compatibility with multiplication/Existence of the multiplicative inverse/Definition of division/Modulative property.

3) x^{2}-2\cdot x = 2\cdot x^{2} Distributive property/a^{b}\cdot a^{c} = a^{b+c}

4) x^{2} + 2\cdot x = 0 Compatibility with addition/Existence of the additive inverse/Modulative property/Reflexive property

5) x \cdot (x+2) = 0 Distributive property/a^{b}\cdot a^{c} = a^{b+c}

6) x = 0\, \lor\, x = -2 Result

Now we check the rational equation with each root:

x = 0

\frac{x}{2} = \frac{x^{2}}{x-2}

\frac{0}{2} = \frac{0^{2}}{0-2}

0 = \frac{0}{-2}

0 = 0

x = 0 is a solution of the rational equation.

x = -2

\frac{x}{2} = \frac{x^{2}}{x-2}

\frac{-2}{2} =  \frac{(-2)^{2}}{-2-2}

-1 = -1

x = -2 is a solution of the rational equation.

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Answer:

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Step-by-step explanation:

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If I understood correctly
7 0
2 years ago
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