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viva [34]
3 years ago
7

I will give you 50 if you helped me thanks

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
5 0

Answer:

it's 40!

10 x 10 = 100

10 x 4 = 40

6 x 10 = 60

and 6 x 4 = 24 !!

kozerog [31]3 years ago
3 0
Your answer would be 40

Cause 10 times 4 is 40
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What is the length of the hypotenuse for a right triangle with legs of length 6 and 8?
Vlad [161]

Answer:

hyp = sqRoot(6^2 + 8^2) = sqRoot(100) = 10

Step-by-step explanation:

6 0
3 years ago
Solve for x: 18 = x/4 + 7
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3 years ago
Read 2 more answers
Please answer
SVEN [57.7K]

From the calculation done below, it can be seen that the cost of one orange is 85 cents.

<h3>How do we determine the cost of a product?</h3>

The cost of one orange can be determined as follows:

One dime = 10 cents

2 dollars = 200 cents

Total amount given by Sue to the store clerk = One dime + 2 dollars = 10 cents + 200 cents = 210 cents

Cost of two oranges = Total amount given by Sue to the store clerk –

Change = 210 cents – 40 cents = 170 cents

Cost of one orange = Cost of two oranges / 2 = 170 cents / 2 = 85 cents

Learn more about cost here: brainly.com/question/14844899.

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7 0
2 years ago
In ΔKLM, k = 700 cm, l = 460 cm and ∠M=78°. Find the length of m, to the nearest centimeter.
pashok25 [27]

Answer:

753

Step-by-step explanation:

m^2 =700^2 +460^-2 −2(700)(460)cos78

m^2 = 490000+211600-2(700)(460)(0.207912)

m^2 = 490000+211600-133895.12889

m^2 = 567704.87111

m=753.462=753

6 0
3 years ago
A geometric sequence is defined by the equation an = (3)3 − n.
Delvig [45]
PART A

The geometric sequence is defined by the equation

a_{n}=3^{3-n}

To find the first three terms, we put n=1,2,3

When n=1,

a_{1}=3^{3-1}

a_{1}=3^{2}

a_{1}=9
When n=2,

a_{2}=3^{3-2}
a_{2}=3^{1}

a_{2}=3

When n=3

a_{3}=3^{3-3}

a_{3}=3^{0}
a_{1}=1
The first three terms are,

9,3,1

PART B

The common ratio can be found using any two consecutive terms.

The common ratio is given by,
r= \frac{a_{2}}{a_{1}}
r = \frac{3}{9}

r = \frac{1}{3}

PART C

To find
a_{11}

We substitute n=11 into the equation of the geometric sequence.

a_{11} = {3}^{3 - 11}

This implies that,

a_{11} = {3}^{ - 8}

a_{11} = \frac{1}{ {3}^{8} }

a_{11}=\frac{1}{6561}
4 0
3 years ago
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