There are total of 5 digits, of which we arrange 3 of them.
Therefore using permutations we can find total possible 3-number combinations.
5P3 = 5*4*3 = 60
To be greater than 600 means first digit must be 6. (1 possibility)
A number is even only if last digit is even, 2 or 4. (2 possibilities)
The 2nd digit then can only be 3,5, (2 or 4). (3 possibilities)
The total possible even 3-digit numbers greater than 600 is product of each digit's possibilities.
---> 1*3*2 = 6
Therefore probability is 6/60 = 1/10.
Answer:
12:3
Step-by-step explanation:
Answer:
(p + q)² - ∛(h·3k) or (p + q)² - ∛(h·3k)
Step-by-step explanation:
Cube root of x: ∛x
Product of h and 3k: h·3k
Sum of p and q: p + q
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From (p + q)² subtract ∛(h·3k) This becomes, symbolically:
=> (p + q)² - ∛(h·3k)
Answer:
y=1/2×2-1
Step-by-step explanation:
x2 – y = 0 yields a parabola.
y = x is straight but has a slope to make it increase/decrease.
2y = x2 yields a parabola.
x2 = 0 yields a parabola.
