There are two possible outcomes of this experiment either success p or failure q. It has a given number of trials and all trials are independent therefore it is<u><em> binomial probability distribution.</em></u>
1- 5 ways
2- 5/16
3- 1/16
4- 1/16
In the question given above n= 5 p =1/2 q= 1/2 r is the given point.
- <u>Part 1:</u>
The number of ways in which different people get off the bus can be calculated using combinations since the order is not essential. Therefore
nCr= 5C4= 5 ways
<u>2. Part 2:</u>
The probability that all four people get off the bus on the first stop is given by :
P (x= 1)= 5C1 (1/2)^0(1/2)^4= 5(1/2)^4= 5/16
<u>3. Part 3:-</u> The probability that all four people get off the bus on the same stop.
P (x= x)= 5C5 (1/2)^0(1/2)^4= 1(1/2)^4= 1/16
<u>4. Part 4-</u> The probability that <u><em>exactly three of the four</em></u> people get off the bus on the same stop.
P (x= x)= 5C5 (1/2)^3(1/2)^1= 1(1/2)^4= 1/16
For binomial distribution click
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Answer:
7 miles per hour
Step-by-step explanation:
3 1/2 miles = 7/2 miles
1/2 hours= 30 minutes
So,
In 30 mins, travelled 7/2 miles
In 1 min, travelled 7/2 ÷ 30= 7/2× 1/30 = (7×1)/(2×30) = 7/60 miles
In 60 mins, travelled (7×60)/60 miles = 420/60 miles = 7 miles.
Hence, the speed is 7 miles per hour.
Hope this helps :)
Answer:
30 < m
The solution would be (30, ∞)
Explanation:
For company A:
The charge is: $96 for any number of mileage ..............> I
For company B:
The charge is $75 fixed and 0.7 for each mileage m. This means that the charge is: 75 + 0.7m .................> II
We want the charge of company A to be less than the charge of company B. This means that we want I to be less than II.
Therefore,
96 < 75 + 0.7m
96 - 75 < 0.7m
21 < 0.7m
21/0.7 < m
30 < m
This means that for any mileage greater than 30, the charge of company A will be less than the charge of company B
Hope this helps :)
