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emmasim [6.3K]
3 years ago
6

There are 56 students going on a field trip to the science center. The students tour the center in groups of 8 how many groups o

f students are there
Mathematics
1 answer:
S_A_V [24]3 years ago
3 0

Answer:

There would be 7 groups of students because 56 divided by 8 students gives you 7 groups.

Step-by-step explanation:

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A common approach to keeping a record of each customer's account receivable is to use a subsidiary accounts receivable ledger.a.
Phantasy [73]

Answer:

True

Step-by-step explanation:

The given statement is true as a common approach to keeping a record of each customer's account receivable is to use a subsidiary accounts receivable ledger. An account's receivable subsidiary ledger  is an accounting ledger that shows the transaction and payment history of each customer to whom the business extends credit.

4 0
2 years ago
4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
2 years ago
In which quadrant of the coordinate plane will the ordered pair (2,-3)
Natalka [10]

The quadrant of the coordinate plane (2,-3) Will be located in is quadrant IV (4)

4 0
2 years ago
34.7985347985 rounded to the nearest tenth
Nina [5.8K]
The answer would be 34.8 I’m pretty sure
7 0
2 years ago
Read 2 more answers
I need help!! Solve -8s-4&gt;3s+3<br> Will mark brainliest!!
iVinArrow [24]

-7/11

Step-by-step explanation:

-8s-4>3s+3=

-8s-3s=3+4

-11s=7

s=-7/11

5 0
3 years ago
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