what i would do is implant some number under 5 for the X's.
Then work it out as if 3 was x so for instance -4(8-3x3)
Answer:
your question is not clear
Step-by-step explanation:
because of option not correct arrange
8x - 9y = 11
Subtract 8x to both sides:
-9y = -8x + 11
Divide -9 to both sides:
y = 8/9x - 11/9
or
y = 8/9x - 1 2/9
Answer:
765 J
Step-by-step explanation:
We are given;
Mass of bucket = 30 kg
Mass of rope = 0.3 kg/m
height of building= 30 meter
Now,
work done lifting the bucket (sand and rope) to the building = work done in lifting the rope + work done in lifting the sand
Or W = W1 + W2
Work done in lifting the rope is given as,
W1 = Force x displacement
W1 = (30,0)∫(0.2x .dx)
Integrating, we have;
W1 = [0.2x²/2] at boundary of 30 and 0
W1 = 0.1(30²)
W1 = 90 J
work done in lifting the sand is given as;
W2 = (30,0)∫(F .dx)
F = mx + c
Where, c = 30 - 15 = 15
m = (30 - 15)/(30 - 0)
m = 15/30 = 0.5
So,
F = 0.5x + 15
Thus,
W2 = (30,0)∫(0.5x + 15 .dx)
Integrating, we have;
W2 = (0.5x²/2) + 15x at boundary of 30 and 0
So,
W2 = (0.5 × 30²)/2) + 15(30)
W2 = 225 + 450
W2 = 675 J
Therefore,
work done lifting the bucket (sand and rope) to the top of the building,
W = 90 + 675
W = 765 J
Answer:
y = 4
Step-by-step explanation:
Given that y varies jointly with x and z then the equation relating them is
y = kxz ← k is the constant of variation
To find k use the condition y = 16 when x = 4 and z = 
, that is
16 = k × 4 × = 2k ( divide both sides by 2 )
8 = k
y = 8xz ← equation of variation
When x = 2 and z = 
, then
y = 8 × 2 × = 16 × = 4
