Step-by-step explanation:
Hey there!
The equation of a line which passes through the point (1,1) is <em>(y-1) = m1 (x-1)...............(i)</em> {using one point formula}
Also, another equation which is perpendicular to the line is <em>y = 1/5 x + 4/5..........(ii)</em>
Comparing equation (ii) with y= mx+c, we get;
Slope (m2) = 1/5.
Now, As per the condition of perpendicular lines,
m1*m2 = -1
or, m1 * 1/2 = -1
or, m1= -2
Therefore, m1 = -2.
Keeping the value of m1 in equation (i) we get;
y-1 = -2(x-1)
y-1 = -2x+1
or, y+2x-2= 0
Therefore, the required equation is 2x+y-2= 0.
Hope it helps!
1) graphs y = -9x + 12 and y = 1/3x - 12 are not coincident.
2) The graphs are not parallel, because the angular coefficients are not equal
3) The condition of perpendicularity:
, where 
- not perpendicular
Answer:
n/4
or 0.25 newtons
Step-by-step explanation:
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