The probabability of winning on at least 1 bet is equal to 1 less the probaility of not winning on either of the 6 bets.
The probability of not wining on any bet is independent of winning or not winning on any of the bets, so the combined probability is calculated as the product of each individual probability.
Each indivitual probability of not winning the is:
(number of not winning outcomes) / (number of possible outcomes) = 37 / 38.
Then, the combined probability of not winning the six times is: (1/38)*(37/38)*(37/38)*(37/38)*(37/38)*(37/38) =(37/38)^6
Therefore, the probability of winning at least one bet is:
= 1 - (37/38)^6 ≈ 1 - 0.973684 ≈ 0.03.
Answer: 0.03.
Answer:
7 is the correct answer. brainliest plese
answer:
△JKI ≅ △CED
step-by-step explanation:
- like i mentioned before, they look similar and fulfill the SSS triangle theorem (this time's the theorem is different only)
Step-by-step explanation:
option 1
option 3
Answer:
x = - 3
Step-by-step explanation:
If you have a look at the screenshot, the asymptote is equal to x=h.
In this case, we look at the bracket (x+3). The h is negative as it does not follow the standard (x-h) model. The value is 3. If we combine these two, the answer would be:
x = -3
