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2 years ago

Please help me on this question. 20 points guaranteed!!

Mathematics

1 answer:

julsineya [31]2 years ago

7 0

Answer:

A cylinder with a volume of 27 $\pi$ cubic inches and a height of 3 inches

Step-by-step explanation:

Volume of a cylinder = $\pi$ r²h
(where r is the radius and h is the height)

Volume = 27 $\pi$

Height = 3

⇒ 27 $\pi$ = 3 $\pi$ r²

⇒ 9 = r²

⇒ r = √9 = 3

So height = radius

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The value of a three digit number if the tens digit is c, the hundreds digit is three less than the tens and the ones digit is 0

raketka [301]

Answer:690 580 470 360 250 140

Step-by-step explanation:

These digits are all numbers that the hundreds digit is three less than the tens digit, the ones digit is also zero

5 0

3 years ago

The ratio of Boys to Girls in Mr. Asante Class is 2 to 3. There are 18 girls in the class. What is the total number of students

ladessa [460]

Answer:

Step-by-step explanation:

2/3 = x/18

2*18 = 3x

36 = 3x

x=12

so there are 12 boys

12+18=30

7 0

3 years ago

Is 5(x+1) the same as 5x+1? Explain your answer.

Morgarella [4.7K]

No
5*x= x (correct)
5*1=5 (incorrect)
When I say correct or incorrect it means that it does/doesn’t match 5x+1

6 0

3 years ago

What is 2+6*5/8 ? I need help with this math problem , thank you.

vampirchik [111]

Hey.

I hope that you're familiar with P.E.M.D.A.S :)

applying PEMDAS :

2 + 6 × 5 ÷ 8

2 + 30 ÷ 8

32 ÷ 8 = 4

Hence, The required answer is 4

Thanks.

8 0

3 years ago

Read 2 more answers

A manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective

Inessa05 [86]

Answer:

(a) P(X $\leq$ 20) = 0.9319

(b) Expected number of defective light bulbs = 15

Step-by-step explanation:

We are given that a manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective independently. A box of 150 bulbs is selected at random.

Firstly, the above situation can be represented through binomial distribution, i.e.;

$P(X=r) = \binom{n}{r} p^{r} (1-p)^{2} ;x=0,1,2,3,....$

where, n = number of samples taken = 150

r = number of success

p = probability of success which in our question is % of bulbs that

are defective, i.e. 10%

Now, we can't calculate the required probability using binomial distribution because here n is very large(n > 30), so we will convert this distribution into normal distribution using continuity correction.

So, Let X = No. of defective bulbs in a box

Mean of X, $\mu$ = $n \times p$ = $150 \times 0.10$ = 15

Standard deviation of X, $\sigma$ = $\sqrt{np(1-p)}$ = $\sqrt{150 \times 0.10 \times (1-0.10)}$ = 3.7

So, X ~ N( $\mu = 15, \sigma^{2} = 3.7^{2})$

Now, the z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

(a) Probability that this box will contain at most 20 defective light bulbs is given by = P(X $\leq$ 20) = P(X < 20.5) ---- using continuity correction

P(X < 20.5) = P( $\frac{X-\mu}{\sigma}$ < $\frac{20.5-15}{3.7}$ ) = P(Z < 1.49) = 0.9319

(b) Expected number of defective light bulbs found in such boxes, on average is given by = E(X) = $n \times p$ = $150 \times 0.10$ = 15.

5 0

3 years ago