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3 years ago

Please help me on this question. 20 points guaranteed!!

Mathematics

1 answer:

julsineya [31]3 years ago

7 0

Answer:

A cylinder with a volume of 27 $\pi$ cubic inches and a height of 3 inches

Step-by-step explanation:

Volume of a cylinder = $\pi$ r²h
(where r is the radius and h is the height)

Volume = 27 $\pi$

Height = 3

⇒ 27 $\pi$ = 3 $\pi$ r²

⇒ 9 = r²

⇒ r = √9 = 3

So height = radius

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The circumference of a circular hot tub at a hotel is 56.5 yards. What is the diameter of the hot tub?

Scorpion4ik [409]

$c = 2\pi \times r \\ 56.5 \div 2 = \pi \times r \\ 28.25 \div \pi = r \\ 9 = r \: then \: \times 2 = d \: \\ diameter \: is \: 18$

7 0

3 years ago

Can someone please help me

gtnhenbr [62]

Answer:

1) B) 10

2) B) 9

Step-by-step explanation:

1) 10x+15=115

10x=100

x=10

2) 12x+17=125

12x=108

x=9

8 0

3 years ago

You spent $145 purchasing 3 student tickets and 7 adult tickets. Adult tickets cost $5 more than a student ticket. Find the cost

vova2212 [387]

Answer:

$11 and $16

Step-by-step explanation:

let x be the cost of a student ticket then an adult ticket is x + 5 , then

3x + 7(x + 5) = 145 , that is

3x + 7x + 35 = 145

10x + 35 = 145 ( subtract 35 from both sides )

10x = 110 ( divide both sides by 10 )

x = 11

Student ticket costs $11 and adult ticket = x + 5 = 11 + 5 = $16

3 0

2 years ago

I need help with my algerbra

Molodets [167]

I can help you what problem??

5 0

3 years ago

Is the binomial a factor of the polynomial nominal function?

Sedbober [7]

The factors for given equation f(x)= $x^{3} +3x^{2} -25x-75$ .

(x-1) - No
(x-3) - No
(x+3) - Yes
(x-5) - Yes
(x+5) - Yes

<u>Step-by-step explanation:</u>

The given equation is f(x)= $x^{3} +3x^{2} -25x-75$ .

Add 0 at the end of the equation.

$x^{3} +3x^{2} -25x-75$ = 0.

Let us group the given equation,

$(x^{3} +3x^{2}) -(25x-75)$ =0.

⇒ Group 1: $x^{3} +3x^{2}$ .

Group 2: $- 25x +75$ .

Pull out factor from each group,

⇒ Group 1: $(x+3)(x^{2})$ .

Group 2: (x+3) (-25).

Join the two group since both (x+3) is common in both groups.

$(x+3)(x^{2} -25)$ =0.

One of the factor is (x+3).

Other factors are solved by the formula, $a^{2}-b^{2} = (a+b) (a-b)$ .

$(x+3)(x^{2} -25)$ = (x+5) (x-5) .

The other factors are (x+5) and (x-5).

7 0

3 years ago