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2 years ago

if a circle of radius 2 is made to roll along the x-axis, what is an equation for the path of the center of the circle?

Mathematics

2 answers:

Blizzard [7]2 years ago

7 0

It would be 2 height above the x axis
it would be y=2

lesantik [10]2 years ago

3 0

The area of the circle is equal to pi multiplied by the square of the radius. the general equation that represents the equation of the circle is x^2 + y^2 = r^2. r is equal to 2 such that r^2 is equal to 4. hence the equation becomes
<span>x^2 + y^2 = 4</span>

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Please answer !!!!!! Will mark brainliest !!!!!!!!

Inga [223]

Answer:

f(u) = 9/5

Step-by-step explanation:

u - 5 = -4(u - 1) Distribute on the right side

u - 5 = -4u + 4

+4u +4u Add 4u to both sides

5u - 5 = 4

+ 5 + 5 Add 5 to both sides

5u = 9 Divide both sides by 5

u = 9/5

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2 years ago

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Mrs. Haines paid $43.94 per gallon for 12.7 gallons of gas. She uses some credit card points to get $0.52 off per gallon. What i

rjkz [21]

3.98 cents a gallon this is a rounded to the nearest hundred

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3 years ago

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What is an equation that models the sequence 400, 200, 100, 50, ?

katrin [286]

N / 2

400 / 2 = 200
200 / 2 = 100
100 / 2 = 50
50 / 2 = 25
25 / 2 = 12.5

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3 years ago

The function a(1) =1/2I^2 describes the area of an isosceles right triangle with leg I. Make a table of values for I=1,2,3 and 4

prohojiy [21]

Functions can be represented using equations, graphs and tables.

The function is given as:

$a(l) = \frac 12 l^2$

When l = 1, we have:

$a(1) = \frac 12 \times 1^2$

$a(1) = 0.5$

When l = 2, we have:

$a(2) = \frac 12 \times 2^2$

$a(2) = 2.0$

When l = 3, we have:

$a(3) = \frac 12 \times 3^2$

$a(3) = 4.5$

When l = 4, we have:

$a(4) = \frac 12 \times 4^2$

$a(4) = 8.0$

Represent the above results as a table, we have:

1 0.5

2 2.0

3 4.5

4 8.0

Read more about tables and functions at:

brainly.com/question/13136492

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2 years ago

Find allgebraiclly the equation of the axis of symmetry and the vertex of the parabola represented by the equation y=-x2-2x+1

Slav-nsk [51]

To find the vertex use -b/2a (for the x value which is also the axis of symmetry)
So 2/-2 = -1 Therefore the axis of symmetry is x=-1 Plug in for the y value:
y= -(-1)^2 -2(-1) + 1 y=-1 + 2 + 1 y=2 Vertex (-1,2)

7 0

3 years ago

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