Please answer these questions using BODMAS:<br> 1) - 4 - 3 x ( - 2 ) <br> 2) 4 + 8 ÷ ( - 2 )

Which graph represents the solution of the system {x^2+y^2=4 <br> X-y=1?

PSYCHO15rus [73]

Answer:

See attached picture.

Step-by-step explanation:

Graph the line using a y-intercept -1 and slope 1.

Graph the equation with vertex (0,0) and radius 2.

6 0

3 years ago

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Mopeds (small motorcycles with an engine capacity below 50 cm3) are very popular in Europe because of their mobility, ease of op

Mashcka [7]

Answer:

a) P(X<50)=0.9827

b) P(X>47)=0.4321

c) P(-1.5<z<1.5)=0.8664

Step-by-step explanation:

We will calculate the probability based on a random sample of one moped out of the population, normally distributed with mean 46.7 and standard deviation 1.75.

a) This means we have to calculate P(x<50).

We will calculate the z-score and then calculate the probability accordign to the standard normal distribution:

$z=\dfrac{X-\mu}{\sigma}=\dfrac{50-46.7}{1.75}=\dfrac{3.7}{1.75}=2.114\\\\\\P(X$

b) We have to calculatee P(x>47).

We will calculate the z-score and then calculate the probability accordign to the standard normal distribution:

$z=\dfrac{X-\mu}{\sigma}=\dfrac{47-46.7}{1.75}=\dfrac{0.3}{1.75}=0.171\\\\\\P(X>47)=P(z>0.171)=0.4321$

c) If the value differs 1.5 standard deviations from the mean value, we have a z-score of z=1.5

$z=\dfrac{(\mu+1.5\sigma)-\mu}{\sigma}=\dfrac{1.5\sigma}{\sigma}=1.5$

So the probability that maximum speed differs from the mean value by at most 1.5 standard deviations is P(-1.5<z<1.5):

$P(-1.5$

3 0

3 years ago

Amanda lives in Fairbanks Alaska she records the low temperature for five days, which days low temperature was 9c colder than th

Brrunno [24]

Answer: all of them they are negitive numbers

Step-by-step explanation:

3 0

3 years ago

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Extreme cold and hot temperatures are known to affect the operation of electronic components. Winter is approaching and you are

Musya8 [376]

Answer:

A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

Test statistic(Z) = 2.31

P-value = 0.0104

Step-by-step explanation:

Step 1

Null hypothesis: The average damaging temperature of nine iPods is 5°F

Alternate hypothesis: The average damaging temperature of nine iPods differs from 5°F

Step 2

Mean=5°F, Sd=3, df=n-1=9-1=8

The t-value corresponding to 8 degrees of freedom and 95% confidence level (5% significance level) is 2.306

Confidence Interval(CI) = (mean + or - t×sd/√n)

CI = (5 + 2.306×3/√8) = 5 + 6.918/2.828= 5+2.45=7.45°F

CI = (5 - 2.306×3/√8) = 5-2.45 = 2.55°F

Z = (sample mean - population mean)/(sd÷√n) = (5-2.55)/(3÷√8) = 2.45/1.061 = 2.31

Step 3

Using the standard distribution table, the cumulative area to the left of Z = 2.31 is 0.9896

P-value = 1 - 0.9896 = 0.0104

Step 4

Conclusion: A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

7 0

3 years ago

HELP! Area of a Trapezoid! 40 points!

kotegsom [21]

FIRST PROBLEM AS GENIUS!!!

The 45-45-90 triangle theorem states that each leg equals x, and the hypotenuse equals $x \sqrt{2}$ . Using this, we can find that the height is 10. Take the average of the lengths to get l = 27.

The area = 270.

7 0

3 years ago

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Please answer these questions using BODMAS: 1) - 4 - 3 x ( - 2 ) 2) 4 + 8 ÷ ( - 2 ) - 3