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3 years ago

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Is 5/6 greater than 5/8

2 answers:

ratelena [41]3 years ago

8 0

5/6 is greater than 5/8

Because:-

5/6 is closer to being a whole number than 5/8 is.

Liono4ka [1.6K]3 years ago

4 0

Yes because fraction wise the denominator that is the smallest is greater. At least that is what I learned

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Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms

miv72 [106K]

<u>Hint </u><u>:</u><u>-</u>

Break the given sequence into two parts .
Notice the terms at gap of one term beginning from the first term .They are like $\dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ . Next term is obtained by multiplying half to the previous term .
Notice the terms beginning from 2nd term , $4,7,10,13$ . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

$\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

$\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]$

Notice the term $\dfrac{1}{2^{25}}$ will be too small , so we can neglect it and take its approximation as 0 .

$\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]$

$\\\implies \boxed{ S_1 \approx 1 }$

$\rule{200}2$

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

$\implies S_2=\dfrac{n}{2}[2a + (n-1)d]$

Substitute ,

$\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}$

Hence sum = 908 + 1 = 909

7 0

3 years ago

Ariel buys 2 fish tanks at the pet store. Each

givi [52]

Answer:

19.4 liters

Step-by-step explanation:

You get 19.4 by multiplying 9.7 by 2 which = 19.4

8 0

3 years ago

Read 2 more answers

Please help!! Write in simplest radical form: √7/8 Show how you figured it out

12345 [234]

Given expression: $\sqrt{\frac{7}{8}}$ .

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$

$=\frac{\sqrt{7}}{\sqrt{8}}$

$\sqrt{8}=\sqrt{2^2\cdot \:2}=2\sqrt{2}$

$\frac{\sqrt{7}}{\sqrt{8}} =\frac{\sqrt{7}}{2\sqrt{2}}$

$\mathrm{Rationalize\:}\frac{\sqrt{7}}{2\sqrt{2}}$

$\mathrm{Multiply\:by\:the\:conjugate}\:\frac{\sqrt{2}}{\sqrt{2}}$

$=\frac{\sqrt{7}\sqrt{2}}{2\sqrt{2}\sqrt{2}}$

$=\frac{\sqrt{14}}{4}$

$=\frac{\sqrt{14}}{4}$ .

3 0

3 years ago

Factoring tables. plzzz help

crimeas [40]

Need more context to answer this question. Please send me the rest of the context

8 0

3 years ago

2(3/5x+3) - (2/3x-1)

motikmotik

6x/5 + 7 + -2x/3

Step-by-step explanation:

i just put it in google lol

3 0

3 years ago