Distance between two points, d, is given by
![d= \sqrt{ ( x_{2} - x_{1}) ^{2} + (y_{2} - y_{1}) ^{2} } ](https://tex.z-dn.net/?f=d%3D%20%5Csqrt%7B%20%28%20x_%7B2%7D%20-%20x_%7B1%7D%29%20%5E%7B2%7D%20%2B%20%28y_%7B2%7D%20-%20y_%7B1%7D%29%20%5E%7B2%7D%20%7D%0A)
where: (x1, y1) = (2, 2) and (x2, y2) = (5, 5)
Answer: x=5 y=6
Step-by-step explanation: 6y=3× +21
6y-6=2× +20
Opposite sides of the rectangle are equal
Substitute 3x +21 into 6y in the second equation.
Answer:
B 32
Step-by-step explanation:
The exterior angle is the sum of the measure of the measure of the opposite interior angles.
151 = 119+b
Subtract 119 from each side.
151-119 = 119-199+b
32 = b
Answer:
The distance A’C’ is 4.47 units
Step-by-step explanation:
Before we go on, we need to get the appropriate transformation
Mathematically, we have a 90 degrees clockwise rotation yielding the following;
(x,y) to (-y,x)
A is (-4,1)
C is (-2,5)
By transforming, we have
A’( -1,-4)
C’ (-5,-2)
To get the magnitude of the line segment, we are going to use the distance formula between points
We have this as;
D = √(x2-x1)^2 + (y2-y1)^2
D = √(-5-(-1))^2 + (-2-(-4))^2
D = √(-4)^2 + (2)^2
D = √(16 + 4)
D = √20
D = 4.47 units