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olga55 [171]
2 years ago
9

which angles are complementary to <2. Select all that apply. 3,5,4 and 1 are all the answer choices

Mathematics
2 answers:
Blizzard [7]2 years ago
8 0

Answer:

only angle 3

Step-by-step explanation:

complementary angles form 90 degree angles.

the only angle that forms a 90 degree angle with angle 2 is angle 3.

erica [24]2 years ago
5 0

<u>Answer:</u>

  • ∠3 is complementary to ∠2

<u>Explanation:</u>

Complementary angles are two angles that sum up to 90°. We already know that ∠2 and ∠x (Unknown angle) must sum up to 90°. We can see that ∠3 is less than 90°, it is adjacent to ∠2, and both angles sum up to 90°. Hence, ∠3 is complementary to ∠2.

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Find the next three sequence of 1,3, 9, 27,<br>​
Andreyy89

Answer: 81, 243, 729

Step-by-step explanation:

<u>STEP ONE: Find a pattern in the sequence</u>

3 ÷ 1 = 3

9 ÷ 3 = 3

27 ÷ 9 = 3

As we can see from the given sequence, each number multiplies 3 to get the next term.

<u>STEP TWO: Find the next three terms</u>

27 × 3 = 81

81 × 3 = 243

243 × 3 = 729

Hope this helps!! :)

Please let me know if you have any questions

4 0
3 years ago
The hypotenuse of a 45°-45°-90° triangle measures 7√2 units. what is the length of one leg of the triangle
Leto [7]
7 because a(one side)= 1/sqrt2 * hypotenuse (7*sqrt2) THis equals 7
8 0
3 years ago
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12x + 3(x - 4) + 2x *<br> Your answer
AleksandrR [38]

Step-by-step explanation:

12x + 3(x - 4) + 2x

17x-12

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8 0
3 years ago
Use the slope formula (m =
lubasha [3.4K]

For (7,2) and (0,5)

slope = 5-3/-7 = -2/7

5 0
3 years ago
birth weights in norway are normally distributed with a mean of 3570 g and a standard deviation of 500g. if the hospital officia
Svetradugi [14.3K]

Answer:

2630 g

Step-by-step explanation:

From the given information:

Given that:

mean (μ) = 3750 g

Standard deviation (σ) = 500

Suppose the hospital officials demand special treatment with a percentage of  lightest 3% (0.03) for newborn babies;

Then, the weight of birth that differentiates the babies that needed special treatment from those that do not can be computed as follows;

P(Z < z₁) = 0.03

Using the Excel Formula; =NORMSINV(0.03) = -1.88

z₁ = - 1.88

Using the test statistics z₁ formula:

z_1 = \dfrac{X-\mu}{\sigma}

-1.88 = \dfrac{X-3570}{500}

By cross multiply, we have:

-1.88 × 500 = X - 3570

-940 = X - 3570

-X = -3570 + 940

-X = -2630

X = 2630 g

Hence, 2630 g is the required weight of birth   that differentiates the babies that needed special treatment from those that do not

6 0
3 years ago
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