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3 years ago

PLEASE HELP

Mathematics

2 answers:

Ymorist [56]3 years ago

5 0

K=-12 that is the answer hope it helps

Helen [10]3 years ago

3 0

$\begin{cases}\large\bf{\green{ \implies}} \tt \: - \frac{6}{5} \: k \: = \: 12 \\ \\ \large\bf{\green{ \implies}} \tt \: - \frac{6k}{5} \: = \: 12 \\ \\ \large\bf{\green{ \implies}} \tt \: - 6k \: = \: 12 \: \times \: 5 \\ \\ \large\bf{\green{ \implies}} \tt \: - 6k \: = \: 60 \\ \\ \large\bf{\green{ \implies}} \tt \: k \: = \: \cancel\frac{60}{ - 6} \\ \\ \large\bf{\green{ \implies}} \tt \: k \: = \: - 10 \end{cases}$

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What is the volume of a cylinder, in cubic feet, with a height of 3 feet and a base diameter of 18 feet?

Xelga [282]

Answer:

763.41 ft

Step-by-step explanation:

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3 years ago

A letter is randomly chosen from the word EXCELLENT. Write each probability as a fraction, decimal, and a percent.

Sergio [31]

Answer:

The answer is below

Step-by-step explanation:

The question is not complete. A complete question is in the form:

A letter is chosen at random from the letters of the word EXCELLENT. Find the probability that letter chosen is i) a vowel ii) a consonant.

Solution:

The total number of letters found in the word EXCELLENT = 9

i) The number of vowel letters found in the word EXCELLENT = {E, E, E} = 3

Hence, probability that letter chosen is a vowel = number of vowels / total number of letters = 3 / 9 = 1 / 3

probability that letter chosen is a vowel = 1/3 = 0.333 = 33.3%

ii) The number of consonant letters found in the word EXCELLENT = {X, C, L, L, N, T} = 6

Hence, probability that letter chosen is a consonant = number of consonant / total number of letters = 6 / 9 = 2 / 3

probability that letter chosen is a consonant = 2/3 = 0.667 = 66.7%

7 0

3 years ago

Solve the system of equations by substitution. 3/8 x + 1/3 y =17/24 and <br> x + 7y = 8

goblinko [34]

$\left \{ {{ \frac{3}{8}x+ \frac{1}{3}y = \frac{17}{14} } \atop {x+7y=8}} \right.$

To solve this system by substitution, first isolate x in the second equation.

$x+7y=8$
$x+7y-7y=8-7y$
$x=8-7y$

Now, plug this expression ( $8-7y$ ) for x in the top equation to solve for y.

$\frac{3}{8} (8-7y)+ \frac{1}{3} y= \frac{17}{14}$
$3- \frac{21}{8} y+ \frac{1}{3} y= \frac{17}{24}$
$72-63y+8y=17$
$72-55y=17$
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$-55y=-55$
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Now that you have y, plug it into the second equation and solve for x.

$x+7y=8$
$x+7(1)=8$
$x+7=8$
$x=1$

Last step is to plug your x- and y-values in to both equations to check your work.

$\frac{3}{8} (1)+ \frac{1}{3} y= \frac{17}{24}$

$\frac{3}{8} * \frac{3}{3} = \frac{9}{24} ; \frac{1}{3} * \frac{8}{8} = \frac{8}{24}$

$\frac{9}{24} + \frac{8}{24} = \frac{17}{24}$ <--True

$1+7(1)=8$
$1+7=8$ <--True

Answer:
$x=1 \\ y=1$

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3 years ago

Read 2 more answers

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Sedbober [7]

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3 years ago