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2 years ago

Help me plz AND PLZ NO LINKS

Mathematics

1 answer:

Nina [5.8K]2 years ago

8 0

Answer:

5. 4.2

6. 100.7

7. 14.8

8. 0.1

9. 24.192

10. 0.0996

11. 213

12. 0.156

Step-by-step explanation:

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Subtracting mixed number 4_1 - 2_7 4 8 4

aleksandr82 [10.1K]

Answer:

$4\frac{1}{4} - 2\frac{7}{8} = 1\frac{3}{8}$

Step-by-step explanation:

Given

$4\frac{1}{4} - 2\frac{7}{8}$ --- proper representation of the question

Required

Evaluate

Convert numbers to improper fractions

$4\frac{1}{4} - 2\frac{7}{8} = \frac{17}{4} - \frac{23}{8}$

Take LCM

$4\frac{1}{4} - 2\frac{7}{8} = \frac{34 - 23}{8}$

$4\frac{1}{4} - 2\frac{7}{8} = \frac{11}{8}$

Convert to improper fraction

$4\frac{1}{4} - 2\frac{7}{8} = 1\frac{3}{8}$

8 0

3 years ago

Triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2). It is translated according to the rule (x, y) → (x – 2, y – 16). Wha

Rudik [331]

The point P has coordinates (x,y) = (-2,6) so x = -2 and y = 6

Replace x and y with those values into the rule given
So,
(x,y) ---> (x-2, y-16)
turns into
(-2,6) ---> (-2-2, 6-16) = (-4,-10)

P = (-2,6)
P ' = (-4,-10)

The answer is -10 because your teacher just wants the y coordinate of point P'

4 0

3 years ago

Help Pls if you want!!!!

Tom [10]

Answer:

Its 2.5 percent ladd enjoy

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A circle has a diameter of 6 centimeters what is the approximate area of the circle

KiRa [710]

Answer:

28.26 $cm^{2}$

Step-by-step explanation:

The radius is half of the diameter. 6/2 = 3, so the radius of this circle is 3 cm.

The formula for the area of a circle is: π $r^{2}$

Plugging 3 into the radius, we have:

$3^{2}$ × π =

9 × π

We can round π to 3.14

9 × 3.14 = 28.26

7 0

3 years ago

What are the ordered pairs of the

9966 [12]

Start by writing the system down, I will use $y$ to represent $f(x)$

$y=x^2-5x+3\wedge y=-3$

Substitute the fact that $y=-3$ into the first equation to get,

$-3=x^2-5x+3$

Simplify into a quadratic form ( $ax^2+bx+c=0$ ),

$x^2-5x+6=0$

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

$x^2+x(m+n)+mn=0$

which then must factor into

$(x+m)(x+n)=0$

And the solutions will be $m,n$ .

Clearly for small coefficients like ours $5,6$ , this is very easy to figure out. To get 5 and 6 we simply say that $m=3, n=2$ .

This fits the definition as $5=3+2$ and $6=2\cdot3$ .

So as mentioned, solutions will equal to $m=3, n=2$ but these are just x-values in the solution pairs of a form $(x,y)$ .

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are $(2,0)$ and $(3,0)$ .

Hope this helps :)

5 0

3 years ago