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Viktor [21]
2 years ago
12

Help me plz AND PLZ NO LINKS

Mathematics
1 answer:
Nina [5.8K]2 years ago
8 0

Answer:

5. 4.2

6. 100.7

7. 14.8

8. 0.1

9.  24.192

10. 0.0996

11. 213

12. 0.156

Step-by-step explanation:

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Subtracting mixed number 4_1 - 2_7 4 8 4
aleksandr82 [10.1K]

Answer:

4\frac{1}{4} - 2\frac{7}{8} = 1\frac{3}{8}

Step-by-step explanation:

Given

4\frac{1}{4} - 2\frac{7}{8} --- proper representation of the question

Required

Evaluate

Convert numbers to improper fractions

4\frac{1}{4} - 2\frac{7}{8} = \frac{17}{4} - \frac{23}{8}

Take LCM

4\frac{1}{4} - 2\frac{7}{8} = \frac{34 - 23}{8}

4\frac{1}{4} - 2\frac{7}{8} = \frac{11}{8}

Convert to improper fraction

4\frac{1}{4} - 2\frac{7}{8} = 1\frac{3}{8}

8 0
3 years ago
Triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2). It is translated according to the rule (x, y) → (x – 2, y – 16). Wha
Rudik [331]
The point P has coordinates (x,y) = (-2,6) so x = -2 and y = 6

Replace x and y with those values into the rule given
So,
(x,y) ---> (x-2, y-16)
turns into
(-2,6) ---> (-2-2, 6-16) = (-4,-10)

P = (-2,6)
P ' = (-4,-10) 

The answer is -10 because your teacher just wants the y coordinate of point P'
4 0
3 years ago
Help Pls if you want!!!!
Tom [10]

Answer:

Its 2.5 percent ladd enjoy

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A circle has a diameter of 6 centimeters what is the approximate area of the circle​
KiRa [710]

Answer:

28.26 cm^{2}

Step-by-step explanation:

The radius is half of the diameter. 6/2 = 3, so the radius of this circle is 3 cm.

The formula for the area of a circle is: πr^{2}

Plugging 3 into the radius, we have:

3^{2} × π =

9 × π

We can round π to 3.14

9 × 3.14 = 28.26

7 0
3 years ago
What are the ordered pairs of the
9966 [12]

Start by writing the system down, I will use y to represent f(x)

y=x^2-5x+3\wedge y=-3

Substitute the fact that y=-3 into the first equation to get,

-3=x^2-5x+3

Simplify into a quadratic form (ax^2+bx+c=0),

x^2-5x+6=0

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

x^2+x(m+n)+mn=0

which then must factor into

(x+m)(x+n)=0

And the solutions will be m,n.

Clearly for small coefficients like ours 5,6, this is very easy to figure out. To get 5 and 6 we simply say that m=3, n=2.

This fits the definition as 5=3+2 and 6=2\cdot3.

So as mentioned, solutions will equal to m=3, n=2 but these are just x-values in the solution pairs of a form (x,y).

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are (2,0) and (3,0).

Hope this helps :)

5 0
3 years ago
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