All categories

3 years ago

Gcdbvfgvfnc vc vfnfbnfnbvgn

Mathematics

1 answer:

jonny [76]3 years ago

7 0

no way dude really? thats so cool

You might be interested in

Plz help me! Thank you soooo much

liraira [26]

Answer:

Step-by-step explanation:

1) drawing a line straight

2) drawing 2 lines diagonally

3) drawing 1 line like this -----

3 0

3 years ago

Read 2 more answers

A product is made up of components A, B, C, D, E, F, G, H, I, and J. Components A, B, C, and F have a 1/10,000 chance of failure

lesantik [10]

Answer:

The overall reliability is 99.7402 %

Step-by-step explanation:

The overall reliability of the product is calculated as the product of the working probability of the components.

For components A,B,C and F we have :

$P(failure)=\frac{1}{10000}$

⇒

$P(Work)=1-\frac{1}{10000}=\frac{9999}{10000}=0.9999$

For components D,E,G and H we have :

$P(failure)=\frac{3}{10000}$

⇒

$P(Work)=1-\frac{3}{10000}=\frac{9997}{10000}=0.9997$

Finally, for components I and J :

$P(failure)=\frac{5}{10000}$

⇒

$P(Work)=1-\frac{5}{10000}=\frac{9995}{10000}=0.9995$

Now we multiply all the working probabilities. We mustn't forget that we have got ten components in this case :

Components A,B,C and F with a working probability of 0.9999

Components D,E,G and H with a working probability of 0.9997

Components I and J with a working probability of 0.9995

Overall reliability = $(0.9999)^{4}(0.9997)^{4}(0.9995)^{2}=0.997402$

0.997402 = 99.7402 %

4 0

3 years ago

PLEASE HELP!!!!!<br> will mark brainliest!!!!!

Nataly [62]

Answer:

x. f(×)

6. 9

7. 7

8. 5

9. 3

10. 1

6 0

2 years ago

members of a soccer team raised $741.15 to go to a tournament. They rented a bus for $250 and budgeted $25.85 per player for mea

blsea [12.9K]

9514 1404 393

Answer:

19 players

Step-by-step explanation:

The total being spent is ...

bus cost + (per player cost) × (number of players) = total raised

250 + 25.85p = 741.15

25.85p = 491.15

p = 491.15/25.85 = 19

The team could bring 19 players to the tournament.

6 0

2 years ago

a silkworm winds its cocoon out of one long silk fiber. to make silk thread, 3 to 10 of these silk fibers are unwound from their

Scorpion4ik [409]

Answer:

Possible lengths of the silk fibre 'x' are 100, 75, 60, 50 and 30 yards respectively.

Step-by-step explanation:

Let the length of the silk fiber = x yards.

Let the number of silk fibres = a.

It is given that the silk fibers between 3 to 10 yards are combined to form a silk thread of 300 yards.

So, we get the equation,

$ax=300$ , where $3\leq a\leq 10$

i.e. $x=\frac{300}{a}$ , $3\leq a\leq 10$

So, the possible values of 'a' are 3, 4, 5, 6 an 10.

Thus, the possible lengths of the silk fibre 'x' are 100, 75, 60, 50 and 30 yards respectively.

3 0

3 years ago