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Arisa [49]
3 years ago
13

+

Mathematics
1 answer:
Aloiza [94]3 years ago
5 0

Answer:

tell ur teacher am not sure about the question

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Which is a factored form of 8x^3+27?
AnnZ [28]
(2x+3)(4xsquared-6x+9)
6 0
2 years ago
Find the sum of deviation of all observations of the data 5, 8, 10, 15, 22 from their mean.​
ivann1987 [24]

Answer:

the sum of deviation of all observations of the data 5, 8, 10, 15, 22 from their mean. =26

Step-by-step explanation:

Mean=sum of observation/ No. of observation

={5+8+ 10+ 15 + 22}/5

=60/5=12

Sum of deviations

= |5- 12| + |8 – 12| + |10- 12| + |15- 12| + |22-12|

= 7+4+2+ 3+ 10

= 26

3 0
2 years ago
I need help with these 2 problems I cant figure out.
Alla [95]

I started by labeling the right angle (Angle C) 90º. Next, I wrote down everything in one equation.

2x + 90 + 3x - 20 = 180º (180 degrees in a triangle)

Next, I add 20 on both sides.

2x + 90 + 3x = 200º

I combine like terms (2x and 3x)

5x + 90 = 200º

I subtract 90 from both sides.

5x = 110º

Divide 110 by 5 to get x.

x = 22

======

For problem two, I label all the angles I know.

49º + 80º + r = 180º

I add 80 and 49.

129º + r = 180º

I subtract 180 and 129 and get 51º, which is your angle for R.

For angle X, you know that angle R plus angle X equals half of a circle, which is 180º

We know from before that 129º is 180º without R, so X is 129º

I hope this helps! Let me know if I'm wrong!

5 0
3 years ago
In an arithmetic sequence, a17 = -40 and
Viktor [21]

Answer:

Tn = 2Tn-1 - Tn-2

Step-by-step explanation:

Before we can generate the recursive sequence, we need to find the nth term of the given sequence.

nth term of an AP is given as:

Tn = a+(n-1)d

If a17 = -40

T17 = a+(17-1)d = -40

a+16d = -40 ...(1)

If a28 = -73

T28 = a+(28-1)d = -73

a+27d = -73 ...(2)

Solving both equations simultaneously using elimination method.

Subtracting 1 from 2 we have:

27d - 16d = -73-(-40)

11d = -73+40

11d = -33

d = -3

Substituting d = -3 into 1

a+16(-3) = -40

a - 48 = -40

a = -40+48

a = 8

Given a = 8, d = -3, the nth term of the sequence will be

Tn = 8+(n-1) (-3)

Tn = 8+(-3n+3)

Tn = 8-3n+3

Tn = 11-3n

Given Tn = 11-3n and d = -3

Tn-1 = Tn - d... (3)

Tn-1 = 11-3n +3

Tn-1 = 14-3n

Tn-2 = Tn-2d...(4)

Tn-2 = 11-3n-2(-3)

Tn-2 = 11-3n+6

Tn-2 = 17-3n

From 3, d = Tn - Tn-1

From 4, d = (Tn - Tn-2)/2

Equating both common difference

(Tn - Tn-2)/2 = Tn - Tn-1

Tn - Tn-2 = 2(Tn - Tn-1)

Tn - Tn-2 = 2Tn-2Tn-1

2Tn-Tn = 2Tn-1 - Tn-2

Tn = 2Tn-1 - Tn-2

The recursive formula will be

Tn = 2Tn-1 - Tn-2

5 0
3 years ago
Read 2 more answers
Simplify the expression. 6(7n – 5m) + 8m
borishaifa [10]
6(7n – 5m) + 8m
42n - 30m + 8m
42n -22m
Answer: 42n-22m

7 0
3 years ago
Read 2 more answers
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