Answer:
<u>2x⁵ + x⁴ - x³ + 6x² + 3x - 3</u>
Step-by-step explanation:
Given :
- f(x) = x³ + 3
- g(x) = 2x² + x - 1
Finding (f × g)(x) :
- f(x) × g(x)
- (x³ + 3)(2x² + x - 1)
- 2x⁵ + 6x² + x⁴ + 3x - x³ - 3
- <u>2x⁵ + x⁴ - x³ + 6x² + 3x - 3</u>
Answer:17/2pi
Explained:
Just writing longer so I don’t have to go into details. If this is on khan academy you don’t have to show your work!
The answer of t he trapezoid area problem is 112.
Answer:
<em> 85% level of the confidence interval is</em>
<em>(26.337, 26.662)</em>
Step-by-step explanation:
<u><em>Explanation</em></u>:-
Given the size of the sample 'n' = 295
Mean of the sample x⁻ = 26.5
The Standard deviation of the Population = 2.7
85% level of the confidence interval is determined by
![(x^{-} - Z_{0.15} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.15} \frac{S.D}{\sqrt{n} })](https://tex.z-dn.net/?f=%28x%5E%7B-%7D%20-%20Z_%7B0.15%7D%20%5Cfrac%7BS.D%7D%7B%5Csqrt%7Bn%7D%20%7D%20%2C%20x%5E%7B-%7D%20%2B%20Z_%7B0.15%7D%20%5Cfrac%7BS.D%7D%7B%5Csqrt%7Bn%7D%20%7D%29)
Critical value Z₀.₁₅ = 1.036
<em> 85% level of the confidence interval is determined by</em>
![(x^{-} - Z_{0.15} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.15} \frac{S.D}{\sqrt{n} })](https://tex.z-dn.net/?f=%28x%5E%7B-%7D%20-%20Z_%7B0.15%7D%20%5Cfrac%7BS.D%7D%7B%5Csqrt%7Bn%7D%20%7D%20%2C%20x%5E%7B-%7D%20%2B%20Z_%7B0.15%7D%20%5Cfrac%7BS.D%7D%7B%5Csqrt%7Bn%7D%20%7D%29)
![(26.9 -1.036 \frac{2.7}{\sqrt{295} } , 26.5 + 1.036 \frac{2.7}{\sqrt{295} })](https://tex.z-dn.net/?f=%2826.9%20-1.036%20%5Cfrac%7B2.7%7D%7B%5Csqrt%7B295%7D%20%7D%20%2C%2026.5%20%2B%201.036%20%5Cfrac%7B2.7%7D%7B%5Csqrt%7B295%7D%20%7D%29)
( 26.5 - 0.1628 , 26.5+0.1628)
(26.3372,26.6628)
Answer:
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Step-by-step explanation:
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