Question

- Given a test statistic of t= 3.018 of a left-tailed test with n= 13, use a 0.01 significance level

Answer 1

Using the t-distribution, it is found that the correct option is:

0.005 < P-value < 0.01, reject the null hypothesis.

What are the hypothesis tested?

At the null hypothesis, it is tested if the mean of a given population is equal to 85, that is:

$H_0: \mu = 85$

We have a left-tailed test, hence, at the alternative hypothesis, it is tested if the mean of the population is less than 85, that is:

$H_1: \mu < 85$

What is the decision?

The test statistic is of t = -3.018.

Using a t-distribution calculator, with test statistic t = -3.018, 13 - 1 = 12 df and a significance level of 0.01, it is found that the p-value for a left-tailed test is of 0.0051.

The p-value is less than 0.01, hence the null hypothesis is rejected and the correct option is:

0.005 < P-value < 0.01, reject the null hypothesis.

More can be learned about the t-distribution at brainly.com/question/16313918