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cupoosta [38]
3 years ago
9

Which list contains only composite numbers?

Mathematics
2 answers:
kiruha [24]3 years ago
7 0
Answer : D. 6,24,51,72,105
stiv31 [10]3 years ago
6 0

Answer:

The last list. 6,24,51,72,105

Step-by-step explanation:

Composite numbers are positive integers that can be formed by multiplying two smaller positive integers. Equivalently, it is a positive integer that has at least one divisor other than 1 and itself.

Hopethishelps    :)

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In ⊙O, ST and VT are tangents. m∠STV = 22°. Find the value of a, b, and m∠SOV.
Rasek [7]

Answer:

\huge \orange {\boxed {a =202\degree}}

\huge \purple {\boxed { b = 158\degree}}

\huge \red {\boxed {m\angle SOV = 158\degree}}

Step-by-step explanation:

In \odot O, ST and VT are tangents at points S and V respectively.

\therefore OS\perp ST, \:and\: OV\perp VT

\therefore m\angle OST=m\angle OVT = 90\degree

In quadrilateral OSTV,

m\angle SOV +m\angle OST+m\angle OVT+m\angle STV = 360\degree

(By interior angle sum postulate of a quadrilateral)

m\angle SOV +90\degree +90\degree +22\degree  = 360\degree

m\angle SOV +202\degree  = 360\degree

m\angle SOV = 360\degree-202\degree

\huge \red {\boxed {m\angle SOV = 158\degree}}

\because b = m\angle SOV

(Measure of minor arc is equal to measure of its corresponding central angle)

\huge \purple {\boxed {\therefore b = 158\degree}}

\because a + b= 360\degree

(By arc sum property of a circle)

\therefore a = 360\degree - b

\therefore a = 360\degree -158\degree

\huge \orange {\boxed {\therefore a =202\degree}}

6 0
3 years ago
Jan completes 50 trials of pulling colored socks out of a box. She pulled green 10
shepuryov [24]

Answer:12

Step-by-step explanation:

8 0
4 years ago
Find the area of each figure. Round to the nearest hundredth where necessary.
Papessa [141]

Answer:

The answer to your question is Triangle's area = 520 in², Square's area = 576 in²

Step-by-step explanation:

Process

1.- Calculate the area of the triangle

-Find the length of the base using the Pythagorean theorem

          c² = a² + b²

-Solve for b²

          b² = c² - a²

-Substitution

          b² = 37² - 35²

-Simplification

          b² = 1369 - 1225

          b² = 144

          b = 12 in

-Find the base

          base = 2(12) = 24 in

-Find the area of the triangle

         Area = base x height / 2

-Substitution

         Area = 24 x 35 / 2

-Simplification

         Area = 420 in²

2.- Find the area of the square

Area = side x side

-Substitution

Area = 24 x 24

-Result

Area = 576 in²

   

3 0
3 years ago
4sin^2 + 13cos^2 = 7. Find cos <br><br> Please read the picture question carefully and help !!
Vanyuwa [196]
4 sin^2 θ + 13cos^2 θ = 7
sin^2 θ = 1 - cos^ θ
4 - 4cos^2 θ + 13cos^2 θ = 7
9cos^2 θ = 3
cos^2 θ = 1/3
cos θ = # (1/3) # - square root
Square root of (1/3) has +1/3 and -1/3 as values of cos
Find the key angle by doing the cos inverse of #1/3
K.A = cos^-1 #(1/3) = 0.955
θ lies in all 4 quadrants
The values of θ are:
θ = 0.955, 2.186, 4.096, 7.23
Ignore 0.955, 2.186, 4.096, 7.23 as they are out of range pi/2 = 1.571
The the value of θ = 0.955 = 0.96 (to 2 d.p) radian

Hope it helped!
5 0
3 years ago
The general solution of 2 y ln(x)y' = (y^2 + 4)/x is
Sav [38]

Replace y' with \dfrac{\mathrm dy}{\mathrm dx} to see that this ODE is separable:

2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}

Integrate both sides; on the left, set u=y^2+4 so that \mathrm du=2y\,\mathrm dy; on the right, set v=\ln x so that \mathrm dv=\dfrac{\mathrm dx}x. Then

\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v

\implies\ln|u|=\ln|v|+C

\implies\ln(y^2+4)=\ln|\ln x|+C

\implies y^2+4=e^{\ln|\ln x|+C}

\implies y^2=C|\ln x|-4

\implies y=\pm\sqrt{C|\ln x|-4}

4 0
3 years ago
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