Answer: Option C)1 over 15 minus 1 over x equals 1 over 20
Explanation:
Since, Micah can fill a box with books in 15 minutes.
Therefore, the work done by Micah in one minute= 1/15
Also, Sydney takes the books out puts them on a shelf.
And the times taken by Micah when Sydney is also taking the books outside from the self= 20 minutes
Therefore, the work done by Micah in one minute when Sydney taking books out of the box= 1/20
Let Sydney alone takes x minutes to take books outsides the shelf.
Then, work done by Sydney in one minute=1/x
Thus, the work done by Sydney( by taking books out of the box)= the work done by Micah - work done by Micah and Sydney simultaneously= 1/15-1/20
⇒1/x=1/15-1/20
⇒1/15-1/20=1/x
⇒1/15-1/x=1/20 is the required expression.
Therefore, Option C is correct.
Answer: the product of the first one is (x-2)/(2)
Step-by-step explanation:
Answer:
P(Sarah wins)= 1/3
P(Bridget wins)= 2/3
Step-by-step explanation:
15/45 = 1/3
1 - 1/3 = 2/3
Answer:
The minimum packs of sausages that he needs is 1 and he needs 2 packs of rolls
Step-by-step explanation:
1 pack of sausages contains 5 sausages and 1 pack of rolls contains 4 rolls. Collin needs the same number of sausages and rolls. He needs 2 packs of bread rolls because 4 x 2 is 8 which means there is enough
hope this helps
Answer:
C
Step-by-step explanation:
Here, we want to find which of the expressions have the greatest rate of exponential growth.
The easiest way to go about this is have a substitution for the term t;
Let’s say t = 6
Thus;
h(t) = 1.18^1 = 1.18
K(t) = 0.375^6 = 0.002780914307
f(t) = 1.36^6 = 6.327518887936
g(t) = 0.86^6 = 0.404567235136
Another way to find this is to express each as a sum of 1
f(t) = (1+ 0.36)^t
g(t) = (1-0.14)^t
k(t) = (1-0.625)^t
We can see clearly that out of all the terms in the brackets asides 1, 0.36 is the biggest in value
