Jewelery maker has
24 jade beads
30 teak Beads
So we need to find the highest common factor for both 24 and 30
The factors for both numbers are
24 -1,2,3,4,6,8,12,24
30 - 1,2,3,5,6,10,15,30
The highest common factor for both is 6
The greatest number of necklaces she can make is 6
Number of jade beads - 24/6 = 4 jade beads
Number of teak beads - 30/6 = 5 teak beads
So each necklace will have 4 jade beads and 5 teak beads
Answer:
8^-2a^7 = a^7/8^2 = a^7/64
Step-by-step explanation:
Answer:
14, 42
Step-by-step explanation:
Set A = {−7, −4, 2, 14, 21, 34, 42}
Set B = {even numbers}
Set C = {multiples of 7}
There is only one question asked
Which numbers in Set A are elements of both Set B and Set C,
We need it to be even and a multiple of 7
14 is even and a multiple of 7 and 42 is even and a multiple of 7
15% of 425
(15/100) * 425
(3/20) * 425
(3/4) * 85
255 / 4
63.75