Given:
The point (15,-11) is on the graph of a one-to-one function f(x).
To find:
The a point on the graph of 
.
Solution:
We know that, if the points on the graph of a one to one function are given by (x,y), then the points on the graph of its inverse function are given by (y,x).
In the point (15,-11).
x-coordinate = 15
y-coordinate = -11
In the inverse function,
x-coordinate = -11
y-coordinate = 15
Therefore, the required point on the graph of is (-11,15).
Answer:
(4x² +3)(x +2)
Step-by-step explanation:
4x³ +8x² +3x +6 = (4x³ +8x²) +(3x +6)
= 4x²(x +2) +3(x +2)
= (4x² +3)(x +2)
__
We assume you want real integers in the factors. Further factoring gets into complex irrational factors.
(2x -i√3)(2x +i√3)(x +2)
Answer:
y = 1/2x -.5
Step-by-step explanation:
We know that is the line is parallel to the equation then the slopes are going to be the same we just have to find the a different y-intercept.
It's a simple as this just plug the points into the equation you have like this.
(-7,-4) (PLUG IN)
-4 = 1/2(-7) +b (I do plus be so we can get another y intercept)
-4 = -3.5 + b (add 3.5 on each side)
-.5 = b
the equation parallel to the first one is...
y = 1/2x -.5
The answer to this question is:
<span>Which form of cell division plays a key role in sexual reproduction?
</span><span>B-"Meiosis"
Hoped This Helped, </span><span>
Kfr48kfr
Your Welcome :) </span>
