35 POINTS

3.2.4 practice modeling slope-intercept Equation of a line

UNO [17]

Answer:

this is from apex

Step-by-step explanation:

1. Which option did you choose? Discuss with another student why you made the choice you made. (1 point)

Troposphere (above the surface) because it looks simpler.

what do you know? the upper crust of the Earth is the layer extending 10 to 40 km beneath the surface. The surface temperature averages 15 degrees Celsius and increases 25 degrees Celsius with each kilometer of depth

what do you want to find out? The range of temperatures I would expect to encounter while traveling within the boundaries of the upper crust.

what answers do you expect to find? a range of temperatures (duh).

Writing an Equation

2. Define the variables you will use in your equation. (1 point)

Let one variable be the distance away from the surface and the other variable be the temperature.

D for distance and T for temperature.

The y-intercept is the starting position at Earth's surface. The coordinates of the y-intercept are (0, the temperature at Earth's surface).

3. What is the b-value of the y-intercept for your equation? (1 point)

15, I finally figured it out after 2 days lol.

The slope is the rate of change for temperature.

If the temperature increases (gets hotter) as the distance from the surface increases, then the slope is positive.

If the temperature decreases (gets colder) as the distance from the surface increases, then the slope is negative.

4. What is the slope of your equation? (1 point)

the slope of my equation is... positive!

5. Write an equation that models the relationship between your variables. (1 point)

umm, let's see... y= 25x+15 with x being each kilometer down from the surface temp. (15).

or if you just need the "equation" equation, then its y=mx+b

Interpreting the Equation

6. Identify and explain what each term represents in the temperature model.

a) The slope (1 point)

25

b) The y-intercept (1 point)

15

Graph the line

7. Identify three points on your line. (1 point)

(10,265) (11,290) (12,315)

8. Using the coordinates from question 7, calculate the slope of your line. Does it match the slope from your model? (2 points)

the slope of my line is 25, just like in my model. (wow magical)

Graph the Equation

9. On the graph below, plot the points and sketch your line. (4 points: 1 for each graphed point, 1 for the line)

see attachment.

Find the Temperature Range

10. Complete the sentence for your layer. (1 point)

The upper crust is the region that starts at Earth's surface and ends between 10 km and 40 km below the Earth's surface.

Use the temperature equation to find the temperature range for your layer.

range: between 265 degrees Celsius and 1015 degrees Celsius. (10km - 40 km)

11. What is the temperature at the end of your layer that is farthest from the surface? (1 point)

1015 degrees celsius.

3 0

3 years ago

Eddie's Evergreens sells Christmas trees and wreaths. Trees cost 3 dollars more than 4 times the price of each wreath. It costs

kari74 [83]

Answer:

$W = 16$

$T = 67$

Step-by-step explanation:

Represent trees with T and wreaths with W

Given

$T = 3 + 4 * W$

$2 * W + T = 99$

Solving (a): Cost of W

Substitute 3 + 4 * W for T in the second equation

$2*W + 3 + 4 * W = 99$

$2W + 3 + 4 W = 99$

Collect Like Terms

$2W + 4 W = 99 - 3$

$6W = 96$

Divide through by 6

$W =\frac{96}{6}$

$W = 16$

Hence, each wreath costs $16

Solving (b): Cost of T

$T = 3 + 4 * W$

Substitute 16 for W

$T = 3 + 4 * 16$

$T = 3 + 64$

$T = 67$

Hence, each tree costs $67

3 0

3 years ago

A company manager for a tire manufacturer is in charge of making sure there is the least amount of defective tires. If the tire

Anestetic [448]

Answer:

0.347% of the total tires will be rejected as underweight.

Step-by-step explanation:

For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.

And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.

1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344

1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792

The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)

Using data from the normal distribution table

P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight

Hope this Helps!!!

6 0

3 years ago

The equation y = [x - 5] +2 is?

Ymorist [56]

Answer:

Groot

Step-by-step explanation:

5 0

3 years ago

Pyramid A is a square pyramid with a base side length of 12 inches and a height of 8 inches. Pyramid B is a square pyramid with

yan [13]

Answer:

The volume of pyramid B is 64 times the volume of pyramid A.

Step-by-step explanation:

Given:

Two square pyramids A and B.

Side Length of A, $s_A =$ 12 inches

Height of A, $h_A =$ 8 inches

Side Length of B, $s_B =$ 48 inches

Height of B, $h_B =$ 32 inches

To find:

How many times bigger is the volume of pyramid B than pyramid A?

OR

$V_B$ is how many times bigger than $V_A$ ?

Solution:

First of all, let us have a look at the formula for volume of a pyramid:

$V=\dfrac{1}{3} \times \text{Area of Base} \times \text{Height}$

Here, base is square, so:

$V=\dfrac{1}{3} \times s^2 \times h$

Volume of pyramid A:

$V_A=\dfrac{1}{3} \times s_A^2 \times h_A$

$\Rightarrow V_A=\dfrac{1}{3} \times 12^2 \times 8 = 384\ inch^3$

Volume of pyramid B:

$V_B=\dfrac{1}{3} \times s_B^2 \times h_B$

$\Rightarrow V_B=\dfrac{1}{3} \times 48^2 \times 32 \\\Rightarrow V_B=\dfrac{1}{3} \times 12^2 \times 8 \times 4^2 \times 4\\\Rightarrow V_B=\dfrac{1}{3} \times 12^2 \times 8 \times 64\\\Rightarrow V_B= 24576\ inch^3 = 384\times 64\ inch^3\\\Rightarrow V_B = V_A\times 64\ inch^3$

The volume of pyramid B is 64 times the volume of pyramid A.

3 0

3 years ago