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2 years ago

Solve the systems of equations through elimination, show work 3+2x-y=0 -3-7y=10x

Mathematics

1 answer:

Wittaler [7]2 years ago

7 0

Answer: x=-1 y=1

Step-by-step explanation:

solve y in 3+2x-y=0

y=3+2x

sub y=3+2x into -3 -7y=10x

-14x- 24= 10x

solve x in -14x-24=10x

x= -1

sub x= -1 into y =3+2x

y=1

so therefore x= -1 and y=1

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Answer:

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Step-by-step explanation:

I multiplied 1.89 times 9 and I got the answer

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3 years ago

Y=5x+1 graph the equation

Dima020 [189]

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3 years ago

Read 2 more answers

Solve 82×41 , show ur work !

lidiya [134]

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2*1=2
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3 years ago

Phonics is an instructional method in which children are taught to connect sounds with letters or groups of letters. A sample of

Fantom [35]

Answer:

A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.645.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.645\frac{23.44}{\sqrt{141}}$

$M = 3.25$

The lower end of the interval is the sample mean subtracted by M. So it is 34.09 - 3.25 = 30.84.

The upper end of the interval is the sample mean added to M. So it is 34.09 + 3.25 = 37.34.

A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).

6 0

3 years ago

* The nth term of sequence A is 3n − 2 The nth term of sequence B is 10 − 2n Sally says there is only one number that is in both

Nina [5.8K]

Answer:

Sally is not right

Step-by-step explanation:

Given the two sequences which have their respective $n^{th}$ terms as following:

Sequence A. $3n - 2$

Sequence B. $10 - 2n$

As per Sally, there exists only one number which is in both the sequences.

To find:

Whether Sally is correct or not.

Solution:

For Sally to be correct, we need to put the $n^{th}$ terms of the respective sequences as equal and let us verify that.

$3n-2=10-2n\\\Rightarrow 3n+2n=10+2\\\Rightarrow 5n=12\\\Rightarrow n = \dfrac{12}{5}$

When we talk about $n^{th}$ terms, $n$ here is a whole number not a fractional number.

But as per the statement as stated by Sally $n$ is a fractional number, only then the two sequences can have a number which is in the both sequences.

Therefore, no number can be in both the sequences A and B.

Hence, Sally is not right.

7 0

2 years ago