Find the area of the circle to the nearest whole number, if necessary!
1 answer:
Answer:
The circle has an area of about 1385 square mm.
Step-by-step explanation:
Let's recall that circles have an area that can be found with the following formula:
where r is the radius of the circle.
Now, focus your eyes on the circle. We are shown that the diameter of this circle is 42 mm, but we only want the radius. Since the radius is half the diameter, the radius is 21 mm. Now, we can solve for the area of the circle.
So, to the nearest whole number, the area of the circle is 1385 square mm.
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Answer:
Step-by-step explanation:
Hello!
There are some values missing, so I'll find the probability distribution using others as example. Afterwards you can calculate the ones corresponding to this exercise following the same steps.
Considering there are 5000 undergraduates registered in the college.
465 are taking one course
658 are taking two courses
566 are taking three courses
1877 are taking four courses
1344 are taking five courses
90 are taking six courses
First you have to define the variable of interest. To identify it you have to ask yourself the following question: what is the characteristic of this population that is being measured?
The answer is "the number of courses an undergraduate is taking" and this will be the study variable X
X can take values from 1 to 6 courses.
To calculate the probability of each value of X, you have to divide the "number of students taking Xi courses" by "total number of students registered in the college"
For
X=1
P(1)= 465/5000= 0.093
X=2
P(2)= 658/5000= 0.1316
X=3
P(3)= 566/5000= 0.1132
X=4
P(4)= 1877/5000= 0.3754
X=5
P(5)= 1344/5000= 0.2688
X=6
P(6)= 90/5000= 0.018
For this to be a probability distribution the following condition should be met:
F(X)= ∑P(X) = 1
In this example: 0.093 + 0.1316 + 0.1132 + 0.3754 + 0.2688 + 0.018 = 1
I hope this helps!
The first term of the arithmetic progression exists at 10 and the common difference is 2.
<h3>How to estimate the common difference of an arithmetic progression?</h3>
let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.
We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula
The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.
9th term = 50
a + 8d = 50 ...............(1)
12th term = 65
a + 11d = 65 ...............(2)
subtract them, (2) - (1), we get
3d = 15
d = 5
If a + 8d = 50 then substitute the value of d = 5, we get
a + 8 5 = 50
a + 40 = 50
a = 50 - 40
a = 10.
Therefore, the first term is 10 and the common difference is 2.
To learn more about common differences refer to:
#SPJ4