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3 years ago

Help me please !!?????????? Question 4

Mathematics

1 answer:

Ne4ueva [31]3 years ago

4 0

from question d = 16t^2 = 56-4t

=》 16t^2 -56 + 4t =0

=》 4t^2 - 14 + t = 0

=》 (4t-7)(t+2) =0

=》 t = 1.75 seconds

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shtirl [24]

Answer:

-cos^4(x)

Step-by-step explanation:

Step 1: Use the Pythagorean identity : 1=cos^2(x) + sin^2(x)

1-sin^2(x) = cos^2(x)

-1+sin^2(x) = -cos^2(x)

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Step 2: Factor out common terms cos^2(x)

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8 0

1 year ago

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velikii [3]

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2 years ago

Tell whether the lines through the given points are parallel, perpendicular, or neither?

Paha777 [63]

$Slope\,\,1=\frac{-1}{slope\,\,2}$

So, Both lines are perpendicular

Step-by-step explanation:

We need to identify if lines:

Line 1: (8,12)(7,-5)

Line 2: (-9,3)(8,2)

are parallel, perpendicular, or neither?

Lines are parallel if they have same slopes i.e slope 1= slope2
Lines are perpendicular if their slopes are negative inverses of each other i.e slope 1= -1/slope 2

The formula used to find slope is:

$Slope=\frac{y_2-y_1}{x_2-x_1}$

Finding Slope of Line 1:

The points are: Line 1: (8,12)(7,-5)

$x_1=8, y_1=12, x_2=7,y_2=-5$

Putting values in the formula:

$Slope\,\,1=\frac{y_2-y_1}{x_2-x_1}$

$Slope\,\,1=\frac{-5-(12)}{7-8}$

$Slope\,\,1=\frac{-5-12}{-1}$

$Slope\,\,1=\frac{-17}{-1}$

$Slope\,\,1=17$

So, Slope of line 1 is 17

Finding Slope of Line 2:

The points are: Line 2: (-9,3)(8,2)

$x_1=-9, y_1=3, x_2=8,y_2=2$

Putting values in the formula:

$Slope\,\,2=\frac{y_2-y_1}{x_2-x_1}$

$Slope\,\,2=\frac{2-(3)}{8-(-9)}$

$Slope\,\,2=\frac{2-3}{8+9}$

$Slope\,\,2=\frac{-1}{17}$

So, Slope of line 2 is $\frac{-1}{17}$

Since $Slope\,\,1=\frac{-1}{slope\,\,2}$

So, Both lines are perpendicular

Keywords: Slope of Lines

Learn more about Slope of lines at:

#learnwithBrainly

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3 years ago

I need help on number 15

garri49 [273]

Okay, you now a triangle has 180º degrees and to add to 180º, you have to add all the numbers you have like this:
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x=30 :)

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2 years ago

Which of the following is not a possible answer to a probability question?

tatyana61 [14]

Answer:

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2 years ago