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2 years ago

10

How many triangles are formed by the angles and sides (45°, 108°, 7 cm)--unique triangle, more than one triangle, or no triangle

?

1 answer:

Kruka [31]2 years ago

5 0

Answer:

no triangle triangle is formed

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As part of an insurance company’s training program, participants learn how to conduct an analysis of clients’ insurability. The

hammer [34]

Answer:

1) cpk < 1.33, therefore it is not capable

b) cpk = 1.33, therefore it is capable

c) cpk < 1.33, therefore it is not capable

2) Cpk can never be greater than the Cp, but can be equal to it

Step-by-step explanation:

Upper limit (USL) = 47 minutes and Lower limit (LSL) = 30 minutes

1)

a) mean (μ) = 37 minutes, standard deviation (σ) = 3 minutes

$cpk=min(\frac{USL-\mu}{3\sigma}, \frac{\mu - LSL}{3\sigma})=min(\frac{47-37}{3*3},\frac{37-30}{3*3} )=min(1.11,0.78)=0.78$

$cp=(\frac{USL-LSL}{6\sigma})=\frac{47-30}{6*3}=0.94$

cpk < 1.33, therefore it is not capable

b) mean (μ) = 38 minutes, standard deviation (σ) = 2 minutes

$cpk=min(\frac{USL-\mu}{3\sigma}, \frac{\mu - LSL}{3\sigma})=min(\frac{47-38}{3*2},\frac{38-30}{3*2} )=min(1.5,1.33)=1.33$

$cp=(\frac{USL-LSL}{6\sigma})=\frac{47-30}{6*2}=1.42$

cpk = 1.33, therefore it is capable

c) a) mean (μ) = 38.5 minutes, standard deviation (σ) = 2.9 minutes

$cpk=min(\frac{USL-\mu}{3\sigma}, \frac{\mu - LSL}{3\sigma})=min(\frac{47-38.5}{3*2.9},\frac{38.5-30}{3*2.9} )=min(0.98,0.98)=0.98$

$cp=(\frac{USL-LSL}{6\sigma})=\frac{47-30}{6*2.9}=0.98$

cpk < 1.33, therefore it is not capable

2) Cpk can never be greater than the Cp, but can be equal to it

3 0

2 years ago

there are 11 kids at a birthday party if there are six girls and five boys at the party which fraction of the kids are boys

timofeeve [1]

11 kids total and there’s 6 girls and 5 boys so that means there’s 5/11 boys and for girls it’s 6/11

4 0

2 years ago

Hello , I need help please THANKYOU 100 POINTS

Gnesinka [82]

Step-by-step explanation:

1)

Let x=larger number

y=smaller number

x+y=59

x-y=13

Now adding these two equations we get

2x=72

x=36

Now as x-y=13

y=x-13=36-13=23

y=23

Therefore the larger number is 36 and the smaller number is 23

(or else u could also write)

The numbers are 36 and 23

---------------------------------------------

2)

Let x=first number

y=Second number

x+y=15

2x-y=6

Now adding these two equations we get

3x=21

x=7

Now as x+y=15,

y=15-x=15-7=8

y=8

Therefore the first number is 7 and the second number is 8

-------------------------------------------

3)

Let x=Larger number

y=smaller number

x-y=3

x-3y=-11

Now on subtracting these two equations we get

2y=14

y=7

Now as x-y=3,

x=y+3=7+3=10

x=10

Therefore the larger number is 10 and the smaller number is 7

8 0

1 year ago

Read 2 more answers

Please help!! Which equation represents the parabola shown on the graph?

MatroZZZ [7]

X^2=6y Hope this helps!

6 0

2 years ago

Read 2 more answers

Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate

Leviafan [203]

Answer:

Probability of having student's score between 505 and 515 is 0.36

Given that z-scores are rounded to two decimals using Standard Normal Distribution Table

Step-by-step explanation:

As we know from normal distribution: z(x) = (x - Mu)/SD

where x = targeted value; Mu = Mean of Normal Distribution; SD = Standard Deviation of Normal Distribution

Therefore using given data: Mu (Mean) = 510, SD = 10.4 we have z(x) by using z(x) = (x - Mu)/SD as under:

In our case, we have x = 505 & 515

Approach 1 using Standard Normal Distribution Table:

z for x=505: z(505) = (505-510)/10.4 gives us z(505) = -0.48

z for x=515: z(515) = (515-510)/10.4 gives us z(515) = 0.48

Afterwards using Normal Distribution Tables and rounding the values to two decimals we find the probabilities as under:

P(505) using z(505) = 0.32

Similarly we have:

P(515) using z(515) = 0.68

Now we may find the probability of student's score between 505 and 515 using:

P(505 < x < 515) = P(515)-P(505) = 0.68 - 0.32 = 0.36

PS: The standard normal distribution table is being attached for reference.

Approach 2 using Excel or Google Sheets:

P(x) = norm.dist(x,Mean,SD,Commutative)

P(505) = norm.dist(505,510,10.4,1)

P(515) = norm.dist(515,510,10.4,1)

Probability of student's score between 505 and 515= P(515) - P(505) = 0.36

6 0

2 years ago