h(t) is the height of the diver in feet above the water
Now it asks about the time at which diver reaches the water
When diver reaches the water , the height of diver from water should be zero
So we plug h(t) =0
So
divide whole equation by -16
we can now factor the quadratic equation
So we get
(t+4)(t-3) =0
plug each factor equal to zero and solve for t
t+4 =0 and t-3 =0
So t=-4 and t=3
Now time cannot be negative , So t=3
So time = 3 seconds
It takes 3 seconds for the diver to reach the water
Answer:
You would have to find the area of the whole rectangle without the spece, so it would be 30mm x 15mm, the result would be 450 square mm.
Then you find the area of the empty space which would be 10mm x 8mm, the result: 80 square mm.
You substract the area of the space from the whole rectangle, which would be 370 square mm, this is the area of the figure
A: 45x + 30y = 1350
Since we don’t know how many adults and children are in the group, we use x and y
b: x-intercept= 30 y-intercept=45
To find the x-intercept you need to isolate the variable. 45x/45 = x
Then you do the same thing to the other side. 1350/45 = 30
So x=30
Same thing with the y-intercept.
30y/30 = y 1350/30 = 45
y=45 (Not really sure what it means by “what they represent” but I thinks it’s that there are 30 adult tickets and 45 children tickets )
c: so our points are (30,0) and (0,45) so you would graph that.
To find how many children tickets were bought if there were 20 adult tickets just look at the photo I put. I don’t know how to explain this.
Hope this helps
Given:
The two way table.
To find:
The conditional probability of P(Drive to school | Senior).
Solution:
The conditional probability is defined as:
Using this formula, we get
...(i)
From the given two way table, we get
Drive to school and senior = 25
Senior = 25+5+5
= 35
Total = 2+25+3+13+20+2+25+5+5
= 100
Now,
Substituting these values in (i), we get
Therefore, the required conditional probability is 0.71.
Neato
assuming you mean
remember
in form
a is leading coficient
(h,k) is vertex
k will be the minimum or max value of the function
if a is positive, then the parabola opens up and k is minimum
if a is negative, then the parabola opens down and k is max
given
a is negative
the parabola opens down and k is the max value
it is -3
the max value is -3, which occors at x=2
g(2)=-3 is max
