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Alika [10]
2 years ago
12

The perimeter of a rectangle is 40 inches. If the length is four less than twice the width, find the dimensions and area

Mathematics
1 answer:
Vinvika [58]2 years ago
7 0

Answer:

<u>L = 12 inches and W = 8 inches</u>

<u>Area = 96 in^2</u>

Step-by-step explanation:

Perimeter(P) = 2(width) + 2(length)

Let W = width and L = length

P = 2W + 2L

L = 2W - 4

Substitute:  P = 2W + 2(2W - 4)

P = 6W - 8

P = 40 inches

40 = 6W - 8

6W = 48

W = 8

L = 2W - 4

L = 2(8) - 4

L = 12

<u>L = 12 inches and W = 8 inches</u>

<u>===============================</u>

Check to see if this works:  

P = 2W + 2L

P = 2(12) + 2(8)

P = 24 + 16

P = 40 inches  <u>YES</u>

<u>========</u>

Area = WxL

Area = (12)*(8)

<u>Area = 96 in^2</u>

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