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jenyasd209 [6]
2 years ago
14

What is the solution to this inequality?

Mathematics
1 answer:
lara [203]2 years ago
3 0
I think it’s the 3rd one
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Millimeters<br> Equal 15 centimeters 4 millimeters
Svetradugi [14.3K]

154mm

we know that  1cm = 10 mm

 therefore      15cm= 10*15 mm

                               =  150 mm

and 4 mm

we get total mm= 15cm +4mm

                          = 150mm+4mm

                           = 154 mm                  

mm stands for millimeters and cm stand for centimeters

learn more of millimeter here brainly.com/question/25862563

#SPJ9

5 0
1 year ago
You spent 1/2 of your money at the theater and 1/4 at an arcade. you have $17.50 left. How much money did you originally have?
4vir4ik [10]
You basically add 17.50+17.50=35 and add 35+35=70, reason being is because the 35 is the 1/2 and 17.50 is the 1/4 so 70 is your answer
6 0
3 years ago
Read 2 more answers
Solve for x.<br><br> 18 ÷ x = -2<br><br> x = _____
Eddi Din [679]

Answer:

-9

Step-by-step explanation:

18÷x = -2

18 = -2×x

18 = -2x

-9 = x

x = -9

6 0
3 years ago
Read 2 more answers
What is the value of 2 in 0.259?
anastassius [24]
Ir's 0.2
or two tenths.
You can tell because it's in the tenths digit place, right next to the decimal.
3 0
3 years ago
Honors Geometry QUiz- Please Help
viktelen [127]

Answer:

QUESTION 2:

The area of the polygon is 21.5 units²

QUESTION 3:

The area of the combined figure is 12 + 18.25·π units²

QUESTION 4:

The area of the figure is 40 units²

QUESTION 5

The area of the compost shape is 40 in.²

Step-by-step explanation:

QUESTION 2.

The area of the polygon is given as follows;

The area of two triangles + The area of trapezoid

1/2×6×3 + 1/2×3×4 + 1/2×(6 + 7) = 21.5 units²

QUESTION 3

The diameter of the semicircle, 'd', is given as follows;

d = √(8² + 3²) = √73

The area of the semicircle = π·d²/4 = π·73/4 = 18.25·π unit²

The area of the right triangle beside the semicircle is given as follows;

1/2 × 8 × 3 = 12 unit²

The area of the combined figure = The area of the semicircle + The area of the right triangle

∴ The area of the combined figure = 12 + 18.25·π units²

QUESTION 4:

The dimensions of the parallelogram are;

Width, W = √(4² + 1²) = √(17)

Length, L = √(8² + 2²) = √(68)

The area of the parallelogram, A_R = W × L = √(17) × √(68) = √(17 × 68) = 34

The area of the parallelogram, A_R = 34 units²

The length of a parallel side, 'A', of the parallelogram is A = 6

The height of the parallelogram, is h = 1

The area of the parallelogram is A = B·h = 6 × 1 = 6 units²

The area of the figure is the sum of the area of the rectangle and the area of the parallelogram

Therefore, we have;

The area of the figure = 34 units² + 6 units² = 40 units²

QUESTION 5

The composite shape consists of a triangle and a rectangle

Therefore, we have;

The area of the rectangle = 5 in. × 7 in. = 35 in.²

The area of the triangle = 1/2 × 2 in. × 5 in. = 5 in.²

The area of the compost shape = The area of the rectangle + The area of the triangle

∴ The area of the compost shape = 35 in.² + 5 in.² = 40 in.²

The area of the compost shape = 40 in.².

5 0
3 years ago
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