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Taya2010 [7]
2 years ago
12

Which of the following is a type of special triangle

Mathematics
2 answers:
bogdanovich [222]2 years ago
6 0

Answer:

I think C

Step-by-step explanation:

equilateral, all sides the same

Plus it can't be B bc it doesn't add up to 180 soooo

evablogger [386]2 years ago
4 0
C is the correct answer
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I =125 r=6% t=1 what is p
vfiekz [6]
There is no P in here, you can't solve for P without a P, Or I just don't get the question.
4 0
3 years ago
A city has a population of 230,000 people. Suppose that each year the population grows by 8.5%. What will the population be afte
worty [1.4K]

Answer:

720,682.92

Step-by-step explanation:

8.5% = 0.085

P(t) = Initial Population * (1 + rate)t

P(t) = 230,000(1 + 0.085)t

P(t) = 230,000(1.085)t

P(14) = 230,000(1.085)14

P(14) = 720,682.82

6 0
2 years ago
A sample of 11001100 computer chips revealed that 62b% of the chips fail in the first 10001000 hours of their use. The company's
STALIN [3.7K]

Answer:

Rule

If;

P-value > significance level --- accept Null hypothesis

P-value < significance level --- reject Null hypothesis

Z score > Z(at 90% confidence interval) ---- reject Null hypothesis

Z score < Z(at 90% confidence interval) ------ accept Null hypothesis

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

z score = 1.35

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = 1.35) falls with the region bounded by Z at 0.1 significance level. And also the two-tailed hypothesis P-value is 0.177 which is greater than 0.1. Then we can conclude that we don't have enough evidence to FAIL or reject the null hypothesis, and we can say that at 0.10 significance level the null hypothesis is valid.

Question; A sample of 1100 computer chips revealed that 62% of the chips fail in the first 1000 hours of their use. The company's promotional literature states that 60% of the chips fail in the first 1000 hours of their use. The quality control manager wants to test the claim that the actual percentage that fail is different from the stated percentage. Determine the decision rule for rejecting the null hypothesis, H0, at the 0.10 level.

Step-by-step explanation:

Given;

n=1100 represent the random sample taken

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

Test statistic z score can be calculated with the formula below;

z = (p^−po)/√{po(1−po)/n}

Where,

z= Test statistics

n = Sample size = 1100

po = Null hypothesized value = 0.60

p^ = Observed proportion = 0.62

Substituting the values we have

z = (0.62-0.60)/√{0.60(1-0.60)/1100}

z = 1.354

z = 1.35

To determine the p value (test statistic) at 0.01 significance level, using a two tailed hypothesis.

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = 1.35) falls with the region bounded by Z at 0.1 significance level. And also the two-tailed hypothesis P-value is 0.177 which is greater than 0.1. Then we can conclude that we don't have enough evidence to FAIL or reject the null hypothesis, and we can say that at 0.10 significance level the null hypothesis is valid.

3 0
3 years ago
The chart below shows the distribution of weeds in a yard.
Marrrta [24]

Answer:

Its c,No, this is not a representative sample because each type of weed should be represented in proportion to the number of weeds actually present in the yard.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
4 ft 7in. or = to 56 in
Leviafan [203]

Answer:

4ft 7in = 55 in

Step-by-step explanation:

6 0
3 years ago
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