All categories

3 years ago

What like is perpendicular to the Y equals 6/4 X +4

1 answer:

4 0

Just flip the slope fraction, and make it negative
6 /4 negative reciprocal is -4 / 6
Then replace the slope with the new slope.
y = -4/6 x + 4

You might be interested in

Easy one for you folks. show work. who ate more?

In-s [12.5K]

What is the question

3 0

2 years ago

What is the slope of a line that is perpendicular to the line represented by the equation 3x+4y=12

S_A_V [24]

Since x=8/3 is a vertical line,the slope is undefined,

7 0

3 years ago

Read 2 more answers

The line plot below shows the weight of each of 15 ostrich eggs . What is the total weight of the 3 heaviest eggs

erica [24]

Answer:

D). 6 3/4

Step-by-step explanation:

Given,

The three eggs with the heaviest weights are;

$2\frac{1}{2}$ ounces

$2\frac{1}{4}$ ounces, &

2 ounces

To find,

The total weight of the three heaviest eggs = $2\frac{1}{2}$ ounces + $2\frac{1}{4}$ ounces + 2 ounces

= 5/2 + 9/4 + 2/1

Taking the L.C.M. of 2, 4, and 1,

= 10/4 + 9/4 + 8/4

= (10 + 9 + 8)/4

= 27/4 or 6 3/4

4 0

3 years ago

If you help me I’ll mark brainliest

Dafna11 [192]

Answer:

1= 2x+74

or,

now,

1+3= being straight angle

5 0

3 years ago

Futhe Mathematics <img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2

Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

$\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }$

We can write the numerator as ,

$\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }$

Recall the identity ,

$\longrightarrow (a-b)(a+b)=a^2-b^2$

Using this we have ,

$\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}$

Again , as we know that ,

$\longrightarrow sin^2\phi + cos^2\phi = 1$

Therefore we can rewrite it as ,

$\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}$

Again using the first identity mentioned above ,

$\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}$

Or else we can also write it using ,

$\longrightarrow cos2\phi = cos^2\phi - sin^2\phi$

Therefore ,

$\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}$

And we are done !

$\rule{200}{4}$

Additional info :-

Derivation of cos²x - sin²x = cos2x :-

We can rewrite cos 2x as ,

$\longrightarrow cos(x + x )$

As we know that ,

$\longrightarrow cos(y + z )= cosy.cosz - siny.sinz$

So that ,

$\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)$

On simplifying,

$\longrightarrow cos(x+x) = cos^2x - sin^2x$

Hence,

$\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}$

$\rule{200}{4}$

7 0

2 years ago